Symfony2 - 处理来自内核异常侦听器的请求/响应

Question

我正在为网站构建一个管理面板,我想更改发生404异常时调用的视图,但仅限于管理应用程序.(path: /admin/*)

我已经过度error404.html.twig了解app/Resources/TwigBundle/views/Exception/网站的观点(at ).

我想到了kernel.exception事件监听器,但现在我遇到了两件事:

• 仅当路由以前缀开头时才加载另一个错误视图: /admin/

  $route = $event->getRequest->get('_route')->render()
  //returns NULL
  

• 调用$event->container->get('templating')->render()函数.

当脚本失败时,我最终得到一个无限循环(空白页).

我唯一能做的就是:

• 检索异常代码:

  $exception = $event->getException();
  $code = $exception->getCode();
  

• 创建新响应:

  $response = new Response();
  $event->setResponse($response);
  

有关如何实现这一目标的任何建议？

[编辑]

班级:

namespace Cmt\AdminBundle\EventListener;

use Symfony\Component\DependencyInjection\ContainerInterface;
use Symfony\Bundle\TwigBundle\TwigEngine;

class AdminActionListener
{
    /**
     * @var ContainerInterface
     */
    protected $container;

    /**
     * @var TwigEngine
     */
    protected $templating;


    /**
     * @param ContainerInterface $container
     */
    public function __construct(ContainerInterface $container, TwigEngine $templating){
        // assign value(s)
        $this->container = $container;
        $this->templating = $templating;
    }

    /**
     * 
     * @param GetResponseForExceptionEvent $event
     */
    public function onKernelException(GetResponseForExceptionEvent $event)
    {
        // get exception
        $exception = $event->getException();

        // get path
        $path = $event->getRequest()->getPathInfo();

        /*
        * Redirect response to new 404 error view only
        * on path prefix /admin/ 
            */
        }
}

和services.yml:

services:
    cmt_admin.exception.action_listener:
        class: Cmt\AdminBundle\EventListener\AdminActionListener
        arguments: [@service_container] [@templating]
        tags:
            -   { name: kernel.event_listener, event: kernel.exception, method: onKernelException }

Answer 1

由于某种原因，这有效：

// get exception
$exception = $event->getException();

// get path
$path = $event->getRequest()->getPathInfo();

if ($exception->getStatusCode() == 404 && strpos($path, '/admin') === 0){

    $templating = $this->container->get('templating');

    $response = new Response($templating->render('CmtAdminBundle:Exception:error404.html.twig', array(
        'exception' => $exception
    )));

    $event->setResponse($response);
}

这基本上就是我之前使用不同语法所做的事情......

@dmirkitanov 无论如何，感谢您的帮助！