142 javascript string trim
我怎么能使用Javascript创建一个函数来修剪作为参数传递的字符串到指定的长度,也作为参数传递.例如:
var string = "this is a string";
var length = 6;
var trimmedString = trimFunction(length, string);
// trimmedString should be:
// "this is"
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有人有想法吗?我听说过使用子字符串,但不太明白.
Wil*_*ill 301
为什么不使用substring ... string.substring(0, 7);
第一个参数(0)是起点.第二个参数(7)是结束点(不包括).更多信息在这里.
var string = "this is a string";
var length = 7;
var trimmedString = string.substring(0, length);
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Jon*_*sen 43
将Will的评论复制到答案中,因为我发现它很有用:
var string = "this is a string";
var length = 20;
var trimmedString = string.length > length ?
string.substring(0, length - 3) + "..." :
string;
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谢谢威尔.
对于任何关心https://jsfiddle.net/t354gw7e/ :)的人来说都是一个小问题
xam*_*mir 12
我建议使用扩展代码整洁.请注意,扩展内部对象原型可能会使依赖它们的库变得混乱.
String.prototype.trimEllip = function (length) {
return this.length > length ? this.substring(0, length) + "..." : this;
}
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并使用它像:
var stringObject= 'this is a verrrryyyyyyyyyyyyyyyyyyyyyyyyyyyyylllooooooooooooonggggggggggggsssssssssssssttttttttttrrrrrrrrriiiiiiiiiiinnnnnnnnnnnnggggggggg';
stringObject.trimEllip(25)
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Sri*_*tha 10
优于String.prototype.slice
方法String.prototype.substring
(在substring中,在某些情况下它给出的结果与您期望的不同)。
从左到右修剪字符串:
const str = "123456789";
result = str.slice(0,5); // "12345", extracts first 5 characters
result = str.substring(0,5); // "12345"
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开始索引 > 结束索引:
result = str.slice(5,0); // "", empty string
result = str.substring(5,0); // "12345" , swaps start & end indexes => str.substring(0,5)
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从右向左修剪字符串: (-ve start index)
result = str.slice(-3); // "789", extracts last 3 characters
result = str.substring(-3); // "123456789" , -ve becomes 0 => str.substring(0)
result = str.substring(str.length - 3); // "789"
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https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String/substr
来自链接:
string.substr(start[, length])
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小智 5
let trimString = function (string, length) {
return string.length > length ?
string.substring(0, length) + '...' :
string;
};
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使用案例,
let string = 'How to trim a string to N chars in Javascript';
trimString(string, 20);
//How to trim a string...
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