我试图通过AJAX将表单值发布到php文件.如何收集我的表单值以发送"data"参数?
$.ajax({
type: "POST",
data: "submit=1&username="+username+"&email="+email+"&password="+password+"&passconf="+passconf,
url: "http://rt.ja.com/includes/register.php",
success: function(data)
{
//alert(data);
$('#userError').html(data);
$("#userError").html(userChar);
$("#userError").html(userTaken);
}
});
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HTML:
<div id="border">
<form action="/" id="registerSubmit">
<div id="userError"></div>
Username: <input type="text" name="username" id="username" size="10"/><br>
<div id="emailError" ></div>
Email: <input type="text" name="email" size="10" id="email"/><br>
<div id="passError" ></div>
Password: <input type="password" name="password" size="10" id="password"/><br>
<div id="passConfError" ></div>
Confirm Password: <input type="password" name="passconf" size="10" id="passconf"/><br>
<input type="submit" name="submit" value="Register" />
</form>
</div>
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Rob*_*bin 131
使用serialize方法:
$.ajax({
...
data: $("#registerSubmit").serialize(),
...
})
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文档:serialize()
小智 13
$("#registerSubmit").serialize() // returns all the data in your form
$.ajax({
type: "POST",
url: 'your url',
data: $("#registerSubmit").serialize(),
success: function() {
//success message mybe...
}
});
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var data={
userName: $('#userName').val(),
email: $('#email').val(),
//add other properties similarly
}
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和
$.ajax({
type: "POST",
url: "http://rt.ja.com/includes/register.php?submit=1",
data: data
success: function(html)
{
//alert(html);
$('#userError').html(html);
$("#userError").html(userChar);
$("#userError").html(userTaken);
}
});
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您不必担心其他任何事情。jquery将处理序列化等。您也可以将提交查询字符串参数submit=1附加到数据json对象中。
您可以使用val函数从输入中收集数据:
jQuery("#myInput1").val();
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