Scala:高阶函数中函数参数的默认值

Ale*_*tin 0 scala default-value higher-order-functions

我有高阶函数:

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def\xc2\xa0calculateFusionRiskContract(postCalc:\xc2\xa0DataFrame\xc2\xa0=>\xc2\xa0DataFrame) \n
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如何设置仅返回 postCalc 参数的 postCalc 参数的默认值?没有任何计算?

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def\xc2\xa0calculateFusionRiskContract(postCalc:\xc2\xa0DataFrame\xc2\xa0=>\xc2\xa0DataFrame = ???) \n
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Dmy*_*tin 6

“只返回参数”的函数是identity

def calculateFusionRiskContract(postCalc: DataFrame => DataFrame = identity) = ???
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scala 有恒等函数吗?