如何使用vba在Excel 2007中找到有条件格式化单元格的填充颜色值？

Question

我在Excel 2007中使用颜色比例进行条件格式化,我很难找到条件格式化单元格的填充颜色代码.我知道Interior.Color返回默认颜色值,但在使用条件格式时没有用.我很中庸地意识到这有多么艰难.

谢谢.

Answer 1

您可以访问fomatting条件的内部颜色(而不是单元格当前的颜色),假设这是应用于单元格的第一个条件:

Range("A1").FormatConditions(1).interior.color

这是一个函数,它将返回单元格包含的所有条件格式的颜色代码.如果没有条件,它将不返回任何内容,如果有条件但没有设置颜色,则它会告诉您"无".

Function ConditionalColor(ByVal cell As Range)

Dim colors As String
Dim i As Long

For i = 1 To Range(cell.Address).FormatConditions.count
    If Range(cell.Address).FormatConditions(i).Interior.Color <> 0 Then
        colors = colors & "Condition " & i & ": " & _
        Range(cell.Address).FormatConditions(i).Interior.Color & vbLf
    Else
        colors = colors & "Condition " & i & ": None" & vbLf
    End If
Next

If Len(colors) <> 0 Then
    colors = Left(colors, Len(colors) - 1)
End If

ConditionalColor = colors

End Function

更新:如果你好奇(我是),Excel使用的颜色代码实际上是BGR,而不是RGB.因此,如果您想将代码转换为RGB值,可以使用:

Function GetRGB(ByVal cell As range) As String

Dim R As String, G As String
Dim B As String, hexColor As String
hexCode = Hex(cell.Interior.Color)

'Note the order excel uses for hex is BGR.
B = Val("&H" & Mid(hexCode, 1, 2))
G = Val("&H" & Mid(hexCode, 3, 2))
R = Val("&H" & Mid(hexCode, 5, 2))

GetRGB = R & ":" & G & ":" & B
End Function

Answer 2

嗨您提供的答案无效,因为我使用的是色标,因此它不会返回正常的3个条件值.

经过更多的搜索,我找到了一个有效的解决方法.那就是取数据并将其放入单词然后将其复制回excel,使得范围在单元格中变为真彩色,因此Interior.Color将起作用.我找到了一个已经把它带入VBA的人.如果其他人想要这样做,这里是它的链接.

Answer 3

下面的代码取自VBAExpress，所有功劳都归功于原作者-byundt。

对于 Excel 2007 可能需要修改。

原文链接

Function ConditionalColor(rg As Range, FormatType As String) As Long
     'Returns the color index (either font or interior) of the first cell in range rg. If no _
    conditional format conditions apply, Then returns the regular color of the cell. _
    FormatType Is either "Font" Or "Interior"
    Dim cel As Range
    Dim tmp As Variant
    Dim boo As Boolean
    Dim frmla As String, frmlaR1C1 As String, frmlaA1 As String
    Dim i As Long

     'Application.Volatile    'This statement required if Conditional Formatting for rg is determined by the _
    value of other cells

    Set cel = rg.Cells(1, 1)
    Select Case Left(LCase(FormatType), 1)
    Case "f" 'Font color
        ConditionalColor = cel.Font.ColorIndex
    Case Else 'Interior or highlight color
        ConditionalColor = cel.Interior.ColorIndex
    End Select

    If cel.FormatConditions.Count > 0 Then
         'On Error Resume Next
        With cel.FormatConditions
            For i = 1 To .Count 'Loop through the three possible format conditions for each cell
                frmla = .Item(i).Formula1
                If Left(frmla, 1) = "=" Then 'If "Formula Is", then evaluate if it is True
                     'Conditional Formatting is interpreted relative to the active cell. _
                    This cause the wrong results If the formula isn 't restated relative to the cell containing the _
                    Conditional Formatting--hence the workaround using ConvertFormula twice In a row. _
                    If the Function were Not called using a worksheet formula, you could just activate the cell instead.
                    frmlaR1C1 = Application.ConvertFormula(frmla, xlA1, xlR1C1, , ActiveCell)
                    frmlaA1 = Application.ConvertFormula(frmlaR1C1, xlR1C1, xlA1, xlAbsolute, cel)
                    boo = Application.Evaluate(frmlaA1)
                Else 'If "Value Is", then identify the type of comparison operator and build comparison formula
                    Select Case .Item(i).Operator
                    Case xlEqual ' = x
                        frmla = cel & "=" & .Item(i).Formula1
                    Case xlNotEqual ' <> x
                        frmla = cel & "<>" & .Item(i).Formula1
                    Case xlBetween 'x <= cel <= y
                        frmla = "AND(" & .Item(i).Formula1 & "<=" & cel & "," & cel & "<=" & .Item(i).Formula2 & ")"
                    Case xlNotBetween 'x > cel or cel > y
                        frmla = "OR(" & .Item(i).Formula1 & ">" & cel & "," & cel & ">" & .Item(i).Formula2 & ")"
                    Case xlLess ' < x
                        frmla = cel & "<" & .Item(i).Formula1
                    Case xlLessEqual ' <= x
                        frmla = cel & "<=" & .Item(i).Formula1
                    Case xlGreater ' > x
                        frmla = cel & ">" & .Item(i).Formula1
                    Case xlGreaterEqual ' >= x
                        frmla = cel & ">=" & .Item(i).Formula1
                    End Select
                    boo = Application.Evaluate(frmla) 'Evaluate the "Value Is" comparison formula
                End If

                If boo Then 'If this Format Condition is satisfied
                    On Error Resume Next
                    Select Case Left(LCase(FormatType), 1)
                    Case "f" 'Font color
                        tmp = .Item(i).Font.ColorIndex
                    Case Else 'Interior or highlight color
                        tmp = .Item(i).Interior.ColorIndex
                    End Select
                    If Err = 0 Then ConditionalColor = tmp
                    Err.Clear
                    On Error GoTo 0
                    Exit For 'Since Format Condition is satisfied, exit the inner loop
                End If
            Next i
        End With
    End If

End Function