在NSURLRequest中通过POST发送JSON

Mav*_*1st 10 iphone post objective-c nsurlconnection

我在使用REST API向服务器发送JSON时遇到问题.这是我使用的代码:

NSString *jsonPostBody = [NSString stringWithFormat:@"'json' = '{\"user\":{\"username\":"
                          "\"%@\""
                          ",\"password\":"
                          "\"%@\""
                          "}}'",
                          [username stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding],
                          [password stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];       
NSData *postData = [jsonPostBody dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
NSString *apiPathParams = [NSString stringWithFormat:@"%@",
                           @"getUser"
                           ];

NSURL *url = [NSURL URLWithString:[[apiPath retain] stringByAppendingString:apiPathParams]];    
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url
                                                       cachePolicy:NSURLRequestReloadIgnoringLocalCacheData
                                                   timeoutInterval:180.0];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:postData];
NSString* postDataLengthString = [[NSString alloc] initWithFormat:@"%d", [postData length]];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:postDataLengthString forHTTPHeaderField:@"Content-Length"];
[self internalRequest:request];
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这就是API的样子,如果它是一个html表单:

<form method="post" action="someAPI-URL">
<input name="json" value="{"user":...}" />
</form>
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这是我将POST数据添加到请求时的样子:

json={"user":{"username":"someUser","password":"somePassword"}}
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出于某种原因,我不知道POST数据没有到达服务器.我在dataString的格式化方面做错了吗?我如何格式化我的dataString以便它匹配String如上所示的表格将传递给服务器?

任何帮助将受到高度赞赏.

PS我宁愿不使用ASIHttpRequest,因为我接管了其他人的项目,除了这个post-request之外,其他所有请求都正常.因此,将整个批量更改为其他连接框架将非常耗时.

这是internalRequest Method的源代码

NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:req delegate:self];
NSMutableDictionary *di = [NSMutableDictionary dictionaryWithObject:[[NSMutableData alloc] init] forKey:@"receivedData"];   
[di setObject:[NSString stringWithFormat:@"%i",identifier] forKey:@"identifier"];
if (delegate == nil) 
{ 
    delegate = self;         
}
[di setObject:delegate forKey:@"delegate"];

CFDictionaryAddValue(connectionToInfoMapping, connection, di)
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kla*_*aus 18

因为您尝试提交HTTP POST标头,如

json={"user":{"username":"%@","password":"%@"}},

这个例子完全有资格最终混乱.

它是application/x-www-form-urlencoded整个身体和application/json价值的混合物.

也许解决这个问题的方法:

您可能需要调整该HTTP标头:

 [request setValue:@"application/x-www-form-urlencoded" 
forHTTPHeaderField:@"Content-Type"];
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由于HTTP主体的JSON部分(值)的编码:

[request setHTTPBody:[[jsonPostBody stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding]
                      dataUsingEncoding:NSUTF8StringEncoding 
                   allowLossyConversion:YES]];    
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哪里stringByAddingPercentEscapesUsingEncoding是PHP等效的客观c jabberwocky urlencode.

HTH