abe*_*man 5 c embedded performance interrupt pic
我最近在中断服务例程(ISR)中遇到了这段代码:
\n#define MAX_CHANNELS 4\nstatic uint16_t volatile* ADCVALS[MAX_CHANNELS] = {\n &ADC1BUF0, &ADC1BUF1, &ADC1BUF2, &ADC1BUF3\n};\nstatic uint8_t CHANNELS = 0;\nstatic uint16_t volatile* volatile BUFFER_IDX[MAX_CHANNELS];\n\nvoid __attribute__((interrupt, no_auto_psv)) _AD1Interrupt(void) {\n *(BUFFER_IDX[0]++) = *ADCVALS[0];\n if (CHANNELS >= 1) {\n *(BUFFER_IDX[1]++) = *ADCVALS[1];\n if (CHANNELS >= 2) {\n *(BUFFER_IDX[2]++) = *ADCVALS[2];\n if (CHANNELS >= 3) {\n *(BUFFER_IDX[3]++) = *ADCVALS[3];\n }\n }\n }\n}\n
Run Code Online (Sandbox Code Playgroud)\n它将 1-4 个寄存器值复制到内存中,具体取决于 的值CHANNELS
,该值是 0-3 之间的值,通过 setter 函数在程序中的其他位置设置。
我发现嵌套的 if 非常丑陋,并将其更改为:
\nint i;\nfor (i = 0; i <= CHANNELS; i++) {\n *(BUFFER_IDX[i]++) = *ADCVALS[i];\n}\n
Run Code Online (Sandbox Code Playgroud)\n这立即打破了ISR。这是一个嵌入式系统,PIC24 架构,64 MHz 时钟。ISR 的时间受到严格限制,必须在 1 \xc2\xb5 秒内完成。for 循环显然太慢,而嵌套的 if 足够快。
\n那么我的问题有两个:
\n-O2
)。小智 5
for (int i = 0; i <= CHANNELS; i++) {
*(BUFFER_IDX[i]++) = *ADCVALS[i];
}
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是
mov DWORD PTR [rbp-4], 0
jmp .L2
.L3:
mov eax, DWORD PTR [rbp-4]
cdqe
mov rax, QWORD PTR [rbp-80+rax*8]
mov edx, DWORD PTR [rax]
mov eax, DWORD PTR [rbp-4]
cdqe
mov rax, QWORD PTR [rbp-48+rax*8]
lea rsi, [rax+4]
mov ecx, DWORD PTR [rbp-4]
movsx rcx, ecx
mov QWORD PTR [rbp-48+rcx*8], rsi
mov DWORD PTR [rax], edx
add DWORD PTR [rbp-4], 1
.L2:
mov eax, DWORD PTR [rbp-4]
cmp eax, DWORD PTR [rbp-8]
jle .L3
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和
*(BUFFER_IDX[0]++) = *ADCVALS[0];
if (CHANNELS >= 1) {
*(BUFFER_IDX[1]++) = *ADCVALS[1];
if (CHANNELS >= 2) {
*(BUFFER_IDX[2]++) = *ADCVALS[2];
if (CHANNELS >= 3) {
*(BUFFER_IDX[3]++) = *ADCVALS[3];
}
}
}
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是
mov rax, QWORD PTR [rbp-80]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rbp-48]
lea rcx, [rax+4]
mov QWORD PTR [rbp-48], rcx
mov DWORD PTR [rax], edx
cmp DWORD PTR [rbp-4], 0
jle .L2
mov rax, QWORD PTR [rbp-72]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rbp-40]
lea rcx, [rax+4]
mov QWORD PTR [rbp-40], rcx
mov DWORD PTR [rax], edx
cmp DWORD PTR [rbp-4], 1
jle .L2
mov rax, QWORD PTR [rbp-64]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rbp-32]
lea rcx, [rax+4]
mov QWORD PTR [rbp-32], rcx
mov DWORD PTR [rax], edx
cmp DWORD PTR [rbp-4], 2
jle .L2
mov rax, QWORD PTR [rbp-56]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rbp-24]
lea rcx, [rax+4]
mov QWORD PTR [rbp-24], rcx
mov DWORD PTR [rax], edx
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你如何看到嵌套的 if 会做更少的跳转,但当前的编译器可以优化它,并且使用 -O3 标志你会得到类似的东西
mov eax, DWORD PTR [rsp+12]
test eax, eax
js .L2
mov rax, QWORD PTR [rsp+48]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rsp+16]
mov DWORD PTR [rax], edx
mov eax, DWORD PTR [rsp+12]
test eax, eax
jle .L2
mov rax, QWORD PTR [rsp+56]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rsp+24]
mov DWORD PTR [rax], edx
mov eax, DWORD PTR [rsp+12]
sub eax, 1
jle .L2
mov rax, QWORD PTR [rsp+64]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rsp+32]
mov DWORD PTR [rax], edx
mov eax, DWORD PTR [rsp+12]
cmp eax, 2
jle .L2
mov rax, QWORD PTR [rsp+72]
mov edx, DWORD PTR [rax]
mov rax, QWORD PTR [rsp+40]
mov DWORD PTR [rax], edx
mov eax, DWORD PTR [rsp+12]
.L2:
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与嵌套 if-s 具有 +- 相同的性能