新手问题:为什么我的PHP OR运算符不起作用？

Question

我有一个函数,如果值等于A,C或D,我想显示一些东西.

问题是如果值设置为B或E,则除了B或E设置外,该功能还是ACD设置中的显示数据.

我究竟做错了什么？

$linkp = opensky_featured_image_position(); 

if ( $linkp == 'featuredimg-1' || 'featuredimg-3' || 'featuredimg-4' ) {
    echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
}
if ( $linkp == 'featuredimg-2' ) {
    echo '<h1>L - '. opensky_featured_image_position() .'</h1>';
}

if ( $linkp == 'featuredimg-5' ) {
    echo '<h1>N - '. opensky_featured_image_position() .'</h1>';
}

Answer 1

if ( $linkp == 'featuredimg-1' || 'featuredimg-3' || 'featuredimg-4' ) {
    echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
}

应该

if ( $linkp == 'featuredimg-1' || $linkp == 'featuredimg-3' || $linkp == 'featuredimg-4' ) {
    echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
}

如果定义了$ linkkp的所有值,你可以做这样的事情

$linkArr = array(
    'featuredimg-1' => 'F',
    'featuredimg-2' => 'L',
    'featuredimg-3' => 'F',
    'featuredimg-4' => 'F',
    'featuredimg-5' => 'N',
);

$linkp = opensky_featured_image_position(); 
echo '<h1>'.$linkArr[$linkp].' - '. opensky_featured_image_position() .'</h1>';