在servlet响应中正确编写HTML页面

Question

我有一个部署在http:// ip:8080/simple下
的servlet servlet在包下a.b.c
我有一个a.b.resources命名的html页面Test.html.

html有img一个图像标签.

在我做的servlet中:

htmlFile = MyServlet.class.getResourceAsStream("/a/b/resources/Test.html");
resp.setContentType("text/html");
PrintWriter writer = resp.getWriter();
byte[] bytes=new byte[htmlFile.available()];
htmlFile.read(bytes);
resp.setContentLength(bytes.length);
writer.print(new String(bytes));
writer.flush();
writer.close();

html页面出现在浏览器上,但在图像的位置我看到它的alt描述.
我试过了:

<img alt="Company A" src="./CompanyLogo.jpg">

<img alt="Company A" src="/a/b/resources/CompanyLogo.jpg">

<img alt="Company A" src="CompanyLogo.jpg">

但这些都不起作用.
jpg图像位于/ a/b/c/resources下,即与HTML页面位于同一目录中.
我正在使用嵌入式Jetty.

我在这里乱搞什么？

Answer 1

浏览器正在尝试解析相对于当前请求URI的那些资源(如浏览器地址栏中所示).当然,您的公共Web内容中不存在这些资源,因为您似乎已将它们放在类路径中.

为了解决这个问题,你真的需要解析 HTML和更改所有相关域src和/或href属性 <a>,<img>,<base>,<link>,<script>,<iframe>,等元素,让它们指向一个流这些资源从classpath到HTTP一个servlet响应.

这有点工作,但Jsoup让事情变得简单.这是一个假设您的servlet映射到URL模式的示例/proxy/*.

String proxyURL = request.getContextPath() + "/proxy/";
InputStream input = MyServlet.class.getResourceAsStream("/a/b/resources" + request.getPathInfo());

if (request.getRequestURI().endsWith(".html")) { // A HTML page is been requested.
    Document document = Jsoup.parse(input, "UTF-8", null);

    for (Element element : document.select("[href]")) {
        element.attr("href", proxyURL + element.attr("href"));
    }

    for (Element element : document.select("[src]")) {
        element.attr("src", proxyURL + element.attr("src"));
    }

    response.setContentType("text/html;charset=UTF-8");
    response.setCharacterEncoding("UTF-8");
    response.getWriter().write(document.html());
}
else { // Other resources like images, etc which have been proxied to this servlet.
    response.setContentType(getServletContext().getMimeType(request.getPathInfo()));
    OutputStream output = response.getOutputStream();
    byte[] buffer = new byte[8192];

    for (int length = 0; (length = input.read(buffer)) > 0;) {
        output.write(buffer, 0, length);
    }
}

input.close();

通过http:// yourdomain:yourport/contextname/proxy/test.html打开它.

Answer 2

request.getRequestDispatcher("/a/b/Test.html").forward(请求，响应);