说我有一个像这样的数组:
[
{"timestamp"=>"1", "count"=>4488.0},
{"timestamp"=>"2", "count"=>4622.0},
{"timestamp"=>"3", "count"=>4655.0},
{"timestamp"=>"4", "count"=>4533.0},
{"timestamp"=>"5", "count"=>4439.0},
{"timestamp"=>"6", "count"=>4468.0},
{"timestamp"=>"7", "count"=>4419.0},
{"timestamp"=>"8", "count"=>4430.0},
{"timestamp"=>"9", "count"=>4429.0},
{"timestamp"=>"10", "count"=>4502.0},
{"timestamp"=>"12", "count"=>4497.0},
{"timestamp"=>"13", "count"=>4468.0},
{"timestamp"=>"14", "count"=>4510.0},
{"timestamp"=>"15", "count"=>4547.0},
{"timestamp"=>"16", "count"=>4471.0},
{"timestamp"=>"17", "count"=>4501.0},
{"timestamp"=>"18", "count"=>4451.0},
{"timestamp"=>"19", "count"=>4453.0},
{"timestamp"=>"20", "count"=>4593.0},
{"timestamp"=>"21", "count"=>4540.0},
{"timestamp"=>"22", "count"=>4516.0},
{"timestamp"=>"23", "count"=>4494.0}
]
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我想循环它将每个x项目放在一个新的数组中,所以就像说我想写一个方法,接受一个类似的my_arr.skip(5)东西?我有点卡在这里,不知道该怎么办.任何帮助都将非常感激.
可能的#each_slice可能是你想要的:
# it returns an enumerator, so you could look over it and do whatever
> [1, 2, 3, 4].each_slice(2) {|s| puts s.inspect }
[1, 2]
[3, 4]
# or if you're just looking to group into smaller arrays, you could just...
> [1, 2, 3, 4].each_slice(2).to_a
[[1, 2], [3, 4]]
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