Maps on Plotly (python)：如何获得欧洲卫星地图的良好分辨率？

Question

我想创建这样的卫星地图：https ://plotly.com/python/mapbox-layers/

我尝试用我的数据（来自法国）重现此代码：

import pandas as pd
us_cities = pd.read_csv("https://raw.githubusercontent.com/plotly/datasets/master/us-cities-top-1k.csv")

import plotly.express as px

fig = px.scatter_mapbox(us_cities, lat="lat", lon="lon", hover_name="City", hover_data=["State", "Population"],
                        color_discrete_sequence=["fuchsia"], zoom=3, height=300)
fig.update_layout(
    mapbox_style="white-bg",
    mapbox_layers=[
        {
            "below": 'traces',
            "sourcetype": "raster",
            "sourceattribution": "United States Geological Survey",
            "source": [
                "https://basemap.nationalmap.gov/arcgis/rest/services/USGSImageryOnly/MapServer/tile/{z}/{y}/{x}"
            ]
        }
      ])
fig.update_layout(margin={"r":0,"t":0,"l":0,"b":0})
fig.show()

但我无法按我想要的方式缩放。

我如何选择底图以获得数据区域的良好分辨率？您是否知道一组底图，我可以从中选择一张以法国为中心的底图？

Answer 1

• 看看https://github.com/roblabs/xyz-raster-sources的替代方案
• 使用法国城市数据来构建示例，使用https://services.arcgisonline.com/arcgis/rest/services/World_Imagery/MapServer/tile/{z}/{y}/{x}允许缩放到法国的建筑物级别

import pandas as pd

df = pd.read_csv(
    "https://gist.githubusercontent.com/curran/13d30e855d48cdd6f22acdf0afe27286/raw/0635f14817ec634833bb904a47594cc2f5f9dbf8/worldcities_clean.csv"
).loc[lambda d: d["country"].eq("France")]

import plotly.express as px

fig = px.scatter_mapbox(
    df,
    lat="lat",
    lon="lng",
    hover_name="city",
    hover_data=["population"],
    color_discrete_sequence=["fuchsia"],
    zoom=3,
    height=300,
)
# s = "https://gis.apfo.usda.gov/arcgis/rest/services/NAIP/USDA_CONUS_PRIME/ImageServer/tile/{z}/{y}/{x}"
# s = "https://basemap.nationalmap.gov/arcgis/rest/services/USGSImageryOnly/MapServer/tile/{z}/{y}/{x}"
s = "https://services.arcgisonline.com/arcgis/rest/services/World_Imagery/MapServer/tile/{z}/{y}/{x}"

fig.update_layout(
    mapbox_style="white-bg",
    mapbox_layers=[
        {
            "below": "traces",
            "sourcetype": "raster",
            "sourceattribution": "United States Geological Survey",
            "source": [s],
        }
    ],
)
fig.update_layout(margin={"r": 0, "t": 0, "l": 0, "b": 0})
fig.show()