我编写了一段代码,使用 isNumeric 函数检查输入的数据是否为数字。现在我想指定并检查它是否是一个整数。据我所知,没有像isInteger这样的函数。如何检查数据类型?
我在下面发布了一段代码,我希望它能像这样有意义。如果没有,请告诉我。
感谢您的帮助!
Sub CheckColumnsHardwareDefinition()
Dim ws As Worksheet: Set ws = ThisWorkbook.Sheets("Hardware Definition")
Dim Target As Range
Dim Target2 As Range
Dim lr As Long
Dim lr2 As Long
Dim DblLengthMin As Double
Dim DblLengthMax As Double
Dim DblWeightMin As Double
Dim DblWeightMax As Double
Dim dynamicArray1() As String
Dim dynamicArray2() As String
Dim f1 As Integer
Dim f2 As Integer
f1 = 0
f2 = 0
DblLengthMax = 20000
DblLengthMin = 5
DblWeightMin = 0.0001
DblWeightMax = 10000
lr3 = Application.WorksheetFunction.Max( _
ws.Range("A" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("B" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("C" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("D" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("E" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("F" & ws.Rows.Count).End(xlUp).Row)
For Each Target3 In Range("A2:F" & lr3)
If IsEmpty(Target3) Then
Target3.Interior.ColorIndex = 8
End If
Next Target3
lr = Application.WorksheetFunction.Max( _
ws.Range("C" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("D" & ws.Rows.Count).End(xlUp).Row, _
ws.Range("E" & ws.Rows.Count).End(xlUp).Row)
For Each Target In Range("C2:E" & lr)
If **Not IsNumeric(Target)** Then
f1 = f1 + 1
Target.Interior.ColorIndex = 3
ReDim Preserve dynamicArray1(0 To f1)
dynamicArray1(f1) = "Row " & Target.Row & " Column " & Target.Column & " wrong
entry: " & Target.Value
End If
If **IsNumeric(Target)** And Target.Value > DblLengthMax Or Target.Value <
DblLengthMin
Then
f2 = f2 + 1
Target.Interior.ColorIndex = 46
ReDim Preserve dynamicArray2(0 To f2)
dynamicArray2(f2) = "Row " & Target.Row & " Column " & Target.Column & " wrong
entry: " & Target.Value
End If
Next Target
Inhalt1 = Join(dynamicArray1, vbCrLf)
MsgBox ("Wrong datatype! " & vbCrLf & vbCrLf & f1 & " Datatype Errors (marked
red)" & vbCrLf & "Only numbers can be entered. Check again" & vbCrLf & Inhalt1)
Inhalt2 = Join(dynamicArray2, vbCrLf)
MsgBox ("Entries out of range!" & vbCrLf & vbCrLf & f2 & " Range errors (marked
orange)" & vbCrLf & "The value is out of range. Check for unit [mm] " & vbCrLf &
Inhalt2)
End Sub
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让我们利用 VBA 的“内部”转换
Function isInteger(val As Variant) As Boolean
Dim i As Integer
On Error GoTo EH
i = CInt(val)
If i = val Then ' check if it was cut or not
isInteger = True
Else
isInteger = False
End If
Exit Function
EH:
isInteger = False
End Function
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Asi
声明为integer
i=val
会导致溢出,因此 33000 的结果为 FALSE。如果您不想这样做,则必须声明i
为long
并使用CLng()
简短的版本看起来像这样
Function isInteger(val As Variant) As Boolean
On Error GoTo EH
isInteger = (val = CInt(val))
Exit Function
EH:
End Function
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