ma1*_*w28 47 enums objective-c uiview uiviewanimation ios
该UIKeyboardAnimationCurveUserInfoKey有一个UIViewAnimationCurve值.如何将其转换为相应的UIViewAnimationOptions值以用于options参数+[UIView animateWithDuration:delay:options:animations:completion:]?
// UIView.h
typedef enum {
UIViewAnimationCurveEaseInOut, // slow at beginning and end
UIViewAnimationCurveEaseIn, // slow at beginning
UIViewAnimationCurveEaseOut, // slow at end
UIViewAnimationCurveLinear
} UIViewAnimationCurve;
// ...
enum {
// ...
UIViewAnimationOptionCurveEaseInOut = 0 << 16, // default
UIViewAnimationOptionCurveEaseIn = 1 << 16,
UIViewAnimationOptionCurveEaseOut = 2 << 16,
UIViewAnimationOptionCurveLinear = 3 << 16,
// ...
};
typedef NSUInteger UIViewAnimationOptions;
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显然,我可以使用switch语句创建一个简单的类别方法,如下所示:
// UIView+AnimationOptionsWithCurve.h
@interface UIView (AnimationOptionsWithCurve)
@end
// UIView+AnimationOptionsWithCurve.m
@implementation UIView (AnimationOptionsWithCurve)
+ (UIViewAnimationOptions)animationOptionsWithCurve:(UIViewAnimationCurve)curve {
switch (curve) {
case UIViewAnimationCurveEaseInOut:
return UIViewAnimationOptionCurveEaseInOut;
case UIViewAnimationCurveEaseIn:
return UIViewAnimationOptionCurveEaseIn;
case UIViewAnimationCurveEaseOut:
return UIViewAnimationOptionCurveEaseOut;
case UIViewAnimationCurveLinear:
return UIViewAnimationOptionCurveLinear;
}
}
@end
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但是,有更简单/更好的方式吗?
Noa*_*oon 44
您建议的类别方法是"正确"的方法 - 您不一定能保证这些常量保持其价值.不过,看看它们是如何定义的,似乎你可以做到
animationOption = animationCurve << 16;
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...如果编译器感觉像是在抱怨,可能会使用强制转换为NSUInteger,然后转换为UIViewAnimationOptions.
Dav*_*oni 35
可以说你可以采用你的第一个解决方案,并使其成为内联函数,以节省堆栈推送.它是如此紧密的条件(常量限制等),它应该编译成一个非常小的组件.
编辑:每个@matt,这里你去(Objective-C):
static inline UIViewAnimationOptions animationOptionsWithCurve(UIViewAnimationCurve curve)
{
switch (curve) {
case UIViewAnimationCurveEaseInOut:
return UIViewAnimationOptionCurveEaseInOut;
case UIViewAnimationCurveEaseIn:
return UIViewAnimationOptionCurveEaseIn;
case UIViewAnimationCurveEaseOut:
return UIViewAnimationOptionCurveEaseOut;
case UIViewAnimationCurveLinear:
return UIViewAnimationOptionCurveLinear;
}
}
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斯威夫特3:
extension UIViewAnimationOptions {
init(curve: UIViewAnimationCurve) {
switch curve {
case .easeIn:
self = .curveEaseIn
case .easeOut:
self = .curveEaseOut
case .easeInOut:
self = .curveEaseInOut
case .linear:
self = .curveLinear
}
}
}
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Tom*_*art 18
在Swift你可以做到
extension UIViewAnimationCurve {
func toOptions() -> UIViewAnimationOptions {
return UIViewAnimationOptions(rawValue: UInt(rawValue << 16))
}
}
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Ant*_*nes 11
基于交换机的解决方案的一个问题是它假设不会传递任何选项组合.但实践表明,可能存在假设不成立的情况.我发现的一个实例(至少在iOS 7上)当您获得键盘动画来动画您的内容以及键盘的外观/消失.
如果您收听keyboardWillShow:或keyboardWillHide:通知,然后获得键盘宣布将使用的曲线,例如:
UIViewAnimationCurve curve = [userInfo[UIKeyboardAnimationCurveUserInfoKey] integerValue];
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您可能会获得值7.如果将其传递给switch函数/方法,则无法获得该值的正确转换,从而导致不正确的动画行为.
Noah Witherspoon的回答将返回正确的值.结合这两种解决方案,您可以编写如下内容:
static inline UIViewAnimationOptions animationOptionsWithCurve(UIViewAnimationCurve curve)
{
UIViewAnimationOptions opt = (UIViewAnimationOptions)curve;
return opt << 16;
}
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正如诺亚所指出的,这里的警告是,如果Apple改变了两种类型不再对应的枚举,那么这个函数就会破坏.无论如何使用它的原因是,基于开关的选项在您今天可能遇到的所有情况下都不起作用,而这样做.
iOS 10+
Swift 5
转换UIView.AnimationCurve为 的Swift 替代方案(UIView.AnimationOptions甚至可能不可能)是使用UIViewPropertyAnimator(iOS 10+),它接受UIView.AnimationCurve并且是比UIView.animate.
您很可能会使用UIResponder.keyboardAnimationCurveUserInfoKey,它返回一个NSNumber. 此密钥的文档是(Apple 自己的符号,不是我的):
public class let keyboardAnimationCurveUserInfoKey: String // NSNumber of NSUInteger (UIViewAnimationCurve)
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使用这种方法,我们可以消除任何猜测:
if let kbTiming = notification.userInfo?[UIResponder.keyboardAnimationCurveUserInfoKey] as? NSNumber, // doc says to unwrap as NSNumber
let timing = UIView.AnimationCurve.RawValue(exactly: kbTiming), // takes an NSNumber
let curve = UIView.AnimationCurve(rawValue: timing) { // takes a raw value
let animator = UIViewPropertyAnimator(duration: duration, curve: curve) {
// add animations
}
animator.startAnimation()
}
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