tes*_*123 1004 c# linq group-by
我们假设我们有一个类似的课程
class Person {
internal int PersonID;
internal string car ;
}
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现在我有一个这个类的列表: List<Person> persons;
现在,此列表可以具有多个具有相同PersonID的实例,例如:
persons[0] = new Person { PersonID = 1, car = "Ferrari" };
persons[1] = new Person { PersonID = 1, car = "BMW" };
persons[2] = new Person { PersonID = 2, car = "Audi" };
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有没有办法可以分组personID并获得他拥有的所有汽车的清单?
例如,预期结果将是
class Result {
int PersonID;
List<string> cars;
}
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分组后,我会得到:
results[0].PersonID = 1;
List<string> cars = results[0].cars;
result[1].PersonID = 2;
List<string> cars = result[1].cars;
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从我到目前为止所做的:
var results = from p in persons
group p by p.PersonID into g
select new { PersonID = g.Key, // this is where I am not sure what to do
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有人可以指点我正确的方向吗?
Jon*_*eet 1655
绝对 - 你基本上想要:
var results = from p in persons
group p.car by p.PersonId into g
select new { PersonId = g.Key, Cars = g.ToList() };
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或者作为非查询表达式:
var results = persons.GroupBy(
p => p.PersonId,
p => p.car,
(key, g) => new { PersonId = key, Cars = g.ToList() });
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基本上,组的内容(当作为视图查看时IEnumerable<T>)是p.car给定键存在的投影(在这种情况下)中的任何值的序列.
有关如何GroupBy工作的更多信息,请参阅我关于该主题的Edulinq帖子.
(我已经改名PersonID,以PersonId在上面,遵循.NET命名约定.)
或者,您可以使用Lookup:
var carsByPersonId = persons.ToLookup(p => p.PersonId, p => p.car);
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然后,您可以非常轻松地为每个人获取汽车:
// This will be an empty sequence for any personId not in the lookup
var carsForPerson = carsByPersonId[personId];
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小智 50
var results = from p in persons
group p by p.PersonID into g
select new { PersonID = g.Key,
/**/car = g.Select(g=>g.car).FirstOrDefault()/**/}
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Yog*_*yal 36
var results = from p in persons
group p by p.PersonID into g
select new { PersonID = g.Key, Cars = g.Select(m => m.car) };
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小智 30
你也可以尝试这个.
var results= persons.GroupBy(n => new { n.PersonId, n.car})
.Select(g => new {
g.Key.PersonId,
g.Key.car)}).ToList();
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小智 26
尝试
persons.GroupBy(x => x.PersonId).Select(x => x)
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要么
检查是否有人在您的列表中重复尝试
persons.GroupBy(x => x.PersonId).Where(x => x.Count() > 1).Any(x => x)
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小智 15
首先,设置您的关键字段。然后包括您的其他字段:
var results =
persons
.GroupBy(n => n.PersonId)
.Select(r => new Result {PersonID = r.Key, Cars = r.ToList() })
.ToList()
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Rec*_*diz 13
我已经使用查询语法和方法语法创建了一个工作代码示例.我希望它可以帮助其他人:)
using System;
using System.Linq;
using System.Collections.Generic;
class Person
{
public int PersonId;
public string car ;
}
class Result
{
public int PersonId;
public List<string> Cars;
}
public class Program
{
public static void Main()
{
List<Person> persons = new List<Person>()
{
new Person { PersonId = 1, car = "Ferrari" },
new Person { PersonId = 1, car = "BMW" },
new Person { PersonId = 2, car = "Audi"}
};
//With Query Syntax
List<Result> results1 = (
from p in persons
group p by p.PersonId into g
select new Result()
{
PersonId = g.Key,
Cars = g.Select(c => c.car).ToList()
}
).ToList();
foreach (Result item in results1)
{
Console.WriteLine(item.PersonId);
foreach(string car in item.Cars)
{
Console.WriteLine(car);
}
}
Console.WriteLine("-----------");
//Method Syntax
List<Result> results2 = persons
.GroupBy(p => p.PersonId,
(k, c) => new Result()
{
PersonId = k,
Cars = c.Select(cs => cs.car).ToList()
}
).ToList();
foreach (Result item in results2)
{
Console.WriteLine(item.PersonId);
foreach(string car in item.Cars)
{
Console.WriteLine(car);
}
}
}
}
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结果如下:
1 Ferrari BMW 2 Audi ----------- 1 Ferrari BMW 2 Audi
尝试这个 :
var results= persons.GroupBy(n => n.PersonId)
.Select(g => new {
PersonId=g.Key,
Cars=g.Select(p=>p.car).ToList())}).ToList();
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但从性能角度来看,以下做法在内存使用方面更好、更优化(当我们的数组包含更多项目(例如数百万)):
var carDic=new Dictionary<int,List<string>>();
for(int i=0;i<persons.length;i++)
{
var person=persons[i];
if(carDic.ContainsKey(person.PersonId))
{
carDic[person.PersonId].Add(person.car);
}
else
{
carDic[person.PersonId]=new List<string>(){person.car};
}
}
//returns the list of cars for PersonId 1
var carList=carDic[1];
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