如何从页面源"抓取"内容？

Question

我有这个代码获取页面的HTML源代码:

$page = file_get_contents('http://example.com/page.html');
$page = htmlentities($page);

我想从中搜集一些内容.例如,假设页面的源包含:

<strong>technorati.com</strong><br />
Connection failed<br /><br />Pinging <strong>icerocket.com</strong><br />
Connection failed<br /><br />Pinging <strong>weblogs.com</strong><br />
Done<br /><br />Pinging <strong>newsgator.com</strong><br />
Done<br /><br />Pinging <strong>blo.gs</strong><br />
Done<br /><br />Pinging <strong>feedburner.com</strong><br />
Done<br /><br />Pinging <strong>blogstreet.com</strong><br />
Done<br /><br />Pinging <strong>my.yahoo.com</strong><br />
Connection failed<br /><br />Pinging <strong>moreover.com</strong><br />
Connection failed<br /><br />Pinging <strong>newsisfree.com</strong><br />
Done<br />

有没有办法可以从源代码中删除它并将其存储在变量中,所以它看起来像这样:

technorati.com连接失败
icerocket.com连接失败
eblogs.com完成
Ect.

因为页面是动态的,这就是我遇到问题的原因.我可以搜索源中的每个站点吗？但那我怎么得到它之后的结果呢？(连接失败/完成)非常
感谢您的帮助!

Answer 1

我尝试使用简单的HTML DOM PHP库来抓取多个站点,可以在这里获得:http://simplehtmldom.sourceforge.net/

然后使用这样的代码:

<?php
include_once 'simple_html_dom.php';

$url = "http://slashdot.org/";
$html = file_get_html($url);

//remove additional spaces
$pat[0] = "/^\s+/";
$pat[1] = "/\s{2,}/";
$pat[2] = "/\s+\$/";
$rep[0] = "";
$rep[1] = " ";
$rep[2] = "";

foreach($html->find('h2') as $heading) { //for each heading
        //find all spans with a inside then echo the found text out
        echo preg_replace($pat, $rep, $heading->find('span a', 0)->plaintext) . "\n"; 
}
?>

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