Django多个用户配置文件/子配置文件

Question

我正在尝试使用内部/外部用户特定的配置文件创建一个内部网/外部网,具有通用的通用配置文件.我在这个网站上看了几个答案,但没有一个专门解决我想要做的事情.下面是我到目前为止的(精简版)文件.

创建配置文件模型的最佳方法是什么,每个用户类型都有子配置文件？我尽量不要求自定义身份验证后端.

https://gist.github.com/1196077

Answer 1

我有一个解决方案,我不知道它是否最好,但看到它:

models.py

from django.db import models
from django.contrib.auth.models import User

class Pollster(models.Model):
    """docstring for Polister"""
    user   = models.OneToOneField(User, related_name = 'polister', unique=True)
    cedule = models.CharField( max_length = 100 ) 

class Respondent(models.Model):
    """ """
    born_date   = models.DateField( verbose_name=u'fecha de nacimiento' )
    cedule      = models.CharField( max_length = 100, verbose_name=u'cedula' ) 
    comunity    = models.CharField( max_length = 100, verbose_name=u'comunidad')
    phone       = models.CharField( max_length = 50, verbose_name=u'telefono')
    sanrelation = models.TextField( verbose_name =u'Relacion con SAN')
    user        = models.OneToOneField( User, related_name = 'respondent')

我创建了一个MiddleWare:所以

我创建了middleware.py

from django.contrib.auth.models import User
from encuestas.models import Pollster, Respondent

class RequestMiddleWare(object):
    """docstring for """
    def process_request(self,request):
        if isPollster(request.user):
            request.user.userprofile = Pollster.objects.get( user = request.user.id)
        elif isRespondent(request.user):
            request.user.userprofile = Respondent.objects.get(user = request.user.id)   
        return None   

def isPollster(user):
    return Pollster.objects.filter(user=user.id).exists()

def isRespondent(user):
    return Respondent.objects.filter(user=user.id).exists()

并且您需要为中间件配置settings.py:添加到MIDDLEWARE_CLASSES属性:

'encuestas.middleware.RequestMiddleWare'

encuestas是my_app名称中间件是Middleware文件RequestMiddleWare是中间件类