Pet*_*lik 5 javascript firebase firebase-authentication
我正在尝试实现 signInWithRedirect() 函数,但是 - 奇怪的是,它不起作用。在下面的代码中,Check 2永远Check 3不会被记录 - 并且不会引发错误:
const signInWithGoogle = async () => {
try {
console.log("Check 1")
await signInWithRedirect(auth, googleAuthprovider);
console.log("Check 2")
const result = await getRedirectResult(auth);
console.log("Check 3");
if (result) {
console.log(result.user);
}
} catch (e) {
console.log(e.message.slice(10));
}
};
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另外,如果我使用完全相同的 Google 帐户通过 signInWithPopup() 方法登录,一切都会按预期进行:
const signInWithGoogle = async () => {
const result = await signInWithPopup(auth, googleAuthprovider)
const user = result.user;
console.log(user)
};
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我真的很感激一些帮助。谢谢!
SignInWithRedirect 实际上会离开页面并重定向回您的应用程序,因此您需要在应用程序首次加载时触发的单独函数中处理响应。
import {
signInWithRedirect,
getRedirectResult,
GoogleAuthProvider,
} from "firebase/auth"
const googleAuthProvider = new GoogleAuthProvider()
// On Button Click
const signUpGoogle = async () => {
try {
await signInWithRedirect(auth, googleAuthProvider)
} catch (error: any) {
console.log(error)
}
}
// When the page loads
const debugRedirectResult = async () => {
try {
const result = await getRedirectResult(auth)
if (result) {
const details = getAdditionalUserInfo(result)
console.log(details) // details.isNewUser to determine if a new or returning user
} else {
// Everything is fine
}
} catch (error) {
console.log(error) // Debug errors from redirect response
}
}Run Code Online (Sandbox Code Playgroud)
例如,在 React 中你会这样做:
// Something like an Auth context provider or App.js
React.useEffect(() => {
const debugRedirectResult = async () => {
try {
const result = await getRedirectResult(auth)
if (result) {
const details = getAdditionalUserInfo(result)
console.log(details) // details.isNewUser to determine if a new or returning user
} else {
// Everything is fine
}
} catch (error) {
console.log(error) // Debug errors from redirect response
}
}
signInWithRedirect()
}, [])Run Code Online (Sandbox Code Playgroud)
需要注意的一些事项:
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