如何使用 Swagger 在 @ApiResponse 中添加示例?

Vic*_*tor 6 java spring swagger swagger-ui swagger-2.0

我想在我的方法中添加一个使用 Swagger 的示例,我尝试了一些方法,但没有成功。

我有我的接口,我在其中定义方法:

@Api(value = "test API")
@RequestMapping("/api/v1/product")
public interface TestController {

    @ApiOperation(
            value = "Service that return a Product",
            notes = "This service returns a Product by the ID",
            nickname = "getProductById",
            response = ProductResponse.class)
    @ApiResponses(value = {
            @ApiResponse(code = 200, message = "The request has succeeded.", response = ProductResponse.class),
            @ApiResponse(code = 500, message = "Internal server error.", response = ProductResponse.class) })
    @GetMapping(
            value = "/productById",
            produces = { "application/json" }
    )
    ResponseEntity<ProductResponse> getProductById(@RequestParam(value = "productId", required = true) String productId);
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ProductResponse 类如下:

@Getter
@Setter
@AllArgsConstructor
public class ProductResponse {

    private Product product;
    private CustomException customException;

}
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产品类别如下:

@Getter
@Setter
@AllArgsConstructor
public class Product {

    @JsonProperty("id")
    private String id;

    @JsonProperty("productName")
    private String productName;

    @JsonProperty("productDescription")
    private String productDescription;

    @JsonProperty("unitPrice")
    private Double unitPrice;
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CustomException 类如下:

@Getter
public class CustomException {

    private final String message;
    private final String errorCode;
    private final String errorType;
    private final Exception exceptionDetail;
    
    public CustomException(String message, String errorCode, String errorType, Exception exceptionDetail) {
        this.message = message;
        this.errorCode = errorCode;
        this.errorType = errorType;
        this.exceptionDetail = exceptionDetail;
    }
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当响应为 200 时,响应如下:

{
  "product": {
    "id": "12345",
    "productName": "Product name",
    "productDescription": "This is a description",
    "unitPrice": 3.25
  },
  "customException": null
}
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但是当响应为 500 时,响应如下:

{
  "product": "null,",
  "customException": {
    "message": "/ by zero",
    "errorCode": "500",
    "errorType": "Internal server error",
    "exceptionDetail": null,
    "cause": null,
    "stackTrace": [
      {
        "classLoaderName": "app",
        "moduleName": null,
        "moduleVersion": null,
        "methodName": "getProductById",
        "fileName": "TestControllerImpl.java",
        "lineNumber": 33,
        "className": "com.myproject.testmicroservice.controller.impl.TestControllerImpl",
        "nativeMethod": false
      }
    ]
  }
}
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如何在 @ApiResponse 注释中添加自定义示例?

小智 5

晚上好,希望你一切顺利。在你描述的情况下,我会做这样的事情

@ApiResponses(value = { 
  @ApiResponse(responseCode = "200", description = "Found the book", 
    content = { @Content(mediaType = "application/json", 
      schema = @Schema(implementation = Book.class)) }),
  @ApiResponse(responseCode = "400", description = "Invalid id supplied", 
    content = @Content),
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这里解释了所描述的方法。我认为第 9 段。使用 @Operation 和 @ApiResponses 生成文档对您的案例特别感兴趣。我希望这有帮助,祝你有个美好的夜晚


pri*_*ngi 4

您可能缺少@Operation注释,您将@ApiResponse.

例子:

  import io.swagger.v3.oas.annotations.responses.ApiResponse;
  import io.swagger.v3.oas.annotations.Operation;

  @Operation(responses = {
      @ApiResponse(responseCode = "200", content = @Content(examples = {
          @ExampleObject(name = "getUserAttribute",
                         summary = "Retrieves a User's attributes.",
                         description = "Retrieves a User's attributes.",
                         value = "[{\"value\": [\"area1\", \"area2\", \"area3\"], \"key\":\"GENERAL_AREAS\"}, {\"value\":\"933933933\", \"key\":\"FONyE\"}]")
      }, mediaType = MediaType.APPLICATION_JSON_VALUE))})
  public ResponseEntity<List<UserPreferenceDto>> getUserPreferenceByCode(
      @Pattern(regexp = "\\w+") @PathVariable String userCode, @Parameter(hidden = true) Pageable pageable) {

     ...
  }
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