绘制加权频率矩阵

Question

这个问题与我之前提出的两个不同的问题有关:

1)重现频率矩阵图

2)为累积图添加95%置信区间

我希望在R中重现这个情节:

我已经做到这一点,使用图形下面的代码:

#Set the number of bets and number of trials and % lines
numbet <- 36 
numtri <- 1000 
#Fill a matrix where the rows are the cumulative bets and the columns are the trials
xcum <- matrix(NA, nrow=numbet, ncol=numtri)
for (i in 1:numtri) {
x <- sample(c(0,1), numbet, prob=c(5/6,1/6), replace = TRUE)
xcum[,i] <- cumsum(x)/(1:numbet)
}
#Plot the trials as transparent lines so you can see the build up
matplot(xcum, type="l", xlab="Number of Trials", ylab="Relative Frequency", main="", col=rgb(0.01, 0.01, 0.01, 0.02), las=1)

我的问题是:如何在一次通过中重现顶部图,而不绘制多个样本？

谢谢.

Answer 1

你可以制作这个情节......

...使用此代码:

boring <- function(x, occ) occ/x

boring_seq <- function(occ, length.out){
  x <- seq(occ, length.out=length.out)
  data.frame(x = x, y = boring(x, occ))
}

numbet <- 31
odds <- 6
plot(1, 0, type="n",  
    xlim=c(1, numbet + odds), ylim=c(0, 1),
    yaxp=c(0,1,2),
    main="Frequency matrix", 
    xlab="Successive occasions",
    ylab="Relative frequency"
    )

axis(2, at=c(0, 0.5, 1))    

for(i in 1:odds){
  xy <- boring_seq(i, numbet+1)
  lines(xy$x, xy$y, type="o", cex=0.5)
}

for(i in 1:numbet){
  xy <- boring_seq(i, odds+1)
  lines(xy$x, 1-xy$y, type="o", cex=0.5)
}