Cod*_*oob -1 javascript arrays filter
是否可以让一个数组过滤另一个数组以匹配每个字符?
我有一组日志和一个过滤器,如下所示:
logs = [{id:1, log: "log1"}], {id:2, log: "log2"}, {id:3, log: "fail"}
filter = ["log"]
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它应该返回
[{id:1, log: "log1"}, {id:2, log: "log2"}]
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如果我的过滤器是
filter = ["1", "fai"]
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输出将是
[{id:1, log: "log1"}, {id:3, log: "fail"]
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您可以执行以下操作:
const logs = [{id:1, log: "log1"}, {id:2, log: "log2"}, {id:3, log: "fail"}]
const searches = ["1", "fai"]
const matchingLogs = logs.filter(l => {
return searches.some(term => l.log.includes(term))
})
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