我在MS Visual C#中编写了一个WindowsForms应用程序,我需要两种形式才能相互引用.在我测试时,我在Form1上创建了两个按钮 - 一个按钮显示Form2,另一个按钮隐藏它(代码在下面).
我想对Form2做同样的事情 - 创建隐藏或显示Form1的两个按钮.我使用了与Form1相同的方法,但是当我编译应用程序时,似乎陷入无限循环并且我收到了StackOverflow消息.
如何更改代码以便两个表单能够互相引用?
Form1代码:
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
Form2 frm2;
public Form1()
{
InitializeComponent();
frm2 = new Form2();
}
private void button1_Click(object sender, EventArgs e)
{
frm2.Visible = false;
}
private void button2_Click(object sender, EventArgs e)
{
frm2.Visible = true;
}
}
}
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Form2代码:
namespace WindowsFormsApplication1
{
public partial class Form2 : Form
{
Form1 frm1;
public Form2()
{
InitializeComponent();
frm1 = new Form1();
}
private void button1_Click(object sender, EventArgs e)
{
frm1.Visible = false;
}
private void button2_Click(object sender, EventArgs e)
{
frm1.Visible = true;
}
}
}
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Forms2的代码应该是
namespace WindowsFormsApplication1
{
public partial class Form2 : Form
{
Form1 frm1;
public Form2(Form1 parent)
{
InitializeComponent();
frm1 = parent;
}
private void button1_Click(object sender, EventArgs e)
{
frm1.Visible = false;
}
private void button2_Click(object sender, EventArgs e)
{
frm1.Visible = true;
}
}
}
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即使两者互相交谈,也必须首先创建一个并传递给第二个.
Form1需要进行调整
public Form1()
{
InitializeComponent();
frm2 = new Form2(this);
}
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另一种方法是创建两个并在构造后传递它
namespace WindowsFormsApplication1
{
public class SomewhereElse
{
public void SomeFunction()
{
Form1 form1= new Form1();
Form2 form2= new Form2();
form1.frm2 = form2;
form2.frm1 = form1;
}
}
public partial class Form2 : Form
{
public Form1 frm1 {get; set;}
public Form2(Form1 parent)
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
frm1.Visible = false;
}
private void button2_Click(object sender, EventArgs e)
{
frm1.Visible = true;
}
}
public partial class Form1 : Form
{
public Form2 frm2 {get; set;}
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
frm2.Visible = false;
}
private void button2_Click(object sender, EventArgs e)
{
frm2.Visible = true;
}
}
}
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