And*_*ndy 2 apache-flex flex4.5
我需要有一个Spark列表,根据用户的选择在VerticalLayout和TileLayout之间切换.最明显的方法是创建具有单独布局的两个列表,然后使用States和"includeIn"属性.但是,这不是一个非常好的解决方案,因为我想在切换时在视图中保留相同的项目(如果用户在VerticalLayout中滚动到项目100,然后切换到Tile,我希望项目100立即可见新布局,而不是从第一项开始).
所以我尝试在同一个列表上使用2个布局并使用"includeIn"解决方案.但是,我收到此错误:
"在'layout'的初始化程序中,目标类型为spark.layouts.supportClasses.LayoutBase的多个初始值设定值."
以下是生成此错误的源代码,有人可以建议更好的方法吗?
<?xml version="1.0" encoding="utf-8"?>
<s:View
xmlns:fx="http://ns.adobe.com/mxml/2009"
xmlns:s="library://ns.adobe.com/flex/spark"
xmlns:mx="library://ns.adobe.com/flex/mx"
>
<fx:Script>
<![CDATA[
import mx.collections.ArrayCollection;
[Bindable]
public var myAC:ArrayCollection = new ArrayCollection([
"01","02","03","04","05","06","07","08","09","10",
"11","12","13","14","15","16","17","18","19","20",
"21","22","23","24","25","26","27","28","29","30",
"31","32","33","34","35","36","37","38","39","40",
"41","42","43","44","45","46","47","48","49","50"
]);
public function toggleListTileState():void
{
if(currentState=="ListState") currentState = "TileState"
else currentState = "ListState";
}
]]>
</fx:Script>
<s:actionContent>
<s:Button label="tile" label.TileState="list" click="toggleListTileState()"/>
</s:actionContent>
<s:states>
<s:State name="ListState" />
<s:State name="TileState" />
</s:states>
<s:List
id="list"
width="100%"
height="100%"
dataProvider="{myAC}"
>
<s:layout>
<s:VerticalLayout
includeIn="ListState"
horizontalAlign="justify"
useVirtualLayout="true"
/>
<s:TileLayout
includeIn="TileState"
rowHeight="300"
useVirtualLayout="true"
/>
</s:layout>
</s:List>
</s:View>
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谢谢
你快到了.您可以完全按照您的尝试进行操作,只需稍微改写即可.像这样的东西:
<s:List id="list" width="100%" height="100%" dataProvider="{myAC}">
<s:layout.ListState>
<s:VerticalLayout horizontalAlign="justify" useVirtualLayout="true" />
</s:layout.ListState>
<s:layout.TileState>
<s:TileLayout rowHeight="300" useVirtualLayout="true" />
</s:layout.TileState>
</s:List>
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当你考虑它时,这就像编写状态依赖属性一样,就像这个例子:
<s:List id="list" width.ListState="100" width.TileState="200" />
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唯一的区别是该属性被写为(M)XML标记而不是(M)XML属性.
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