将excel或电子表格列字母转换为Pythonic方式的数字

Question

是否有更多pythonic方式将excel样式列转换为数字(从1开始)？

最多两个字母的工作代码:

def column_to_number(c):
    """Return number corresponding to excel-style column."""
    number=-25
    for l in c:
        if not l in string.ascii_letters:
            return False
        number+=ord(l.upper())-64+25
    return number

代码运行:

>>> column_to_number('2')
False
>>> column_to_number('A')
1
>>> column_to_number('AB')
28

三个字母不起作用.

>>> column_to_number('ABA')
54
>>> column_to_number('AAB')
54

参考: C#中回答的问题

Answer 1

有一种方法可以使它更加pythonic(使用三个或更多字母并使用更少的幻数):

def col2num(col):
    num = 0
    for c in col:
        if c in string.ascii_letters:
            num = num * 26 + (ord(c.upper()) - ord('A')) + 1
    return num

并且作为使用reduce的单线程(不检查输入并且不太可读,因此我不推荐它):

col2num = lambda col: reduce(lambda x, y: x*26 + y, [ord(c.upper()) - ord('A') + 1 for c in col])

Answer 2

在 Python 2.7.1 和 3.5.2 中测试的单行

excel_col_num = lambda a: 0 if a == '' else 1 + ord(a[-1]) - ord('A') + 26 * excel_col_num(a[:-1])

excel_col_name = lambda n: '' if n <= 0 else excel_col_name((n - 1) // 26) + chr((n - 1) % 26 + ord('A'))

多班轮同样

def excel_column_name(n):
    """Number to Excel-style column name, e.g., 1 = A, 26 = Z, 27 = AA, 703 = AAA."""
    name = ''
    while n > 0:
        n, r = divmod (n - 1, 26)
        name = chr(r + ord('A')) + name
    return name

def excel_column_number(name):
    """Excel-style column name to number, e.g., A = 1, Z = 26, AA = 27, AAA = 703."""
    n = 0
    for c in name:
        n = n * 26 + 1 + ord(c) - ord('A')
    return n

def test (name, number):
    for n in [0, 1, 2, 3, 24, 25, 26, 27, 702, 703, 704, 2708874, 1110829947]:
        a = name(n)
        n2 = number(a)
        a2 = name(n2)
        print ("%10d  %-9s  %s" % (n, a, "ok" if a == a2 and n == n2 else "error %d %s" % (n2, a2)))

test (excel_column_name, excel_column_number)
test (excel_col_name, excel_col_num)

所有测试打印

         0             ok
         1  A          ok
         2  B          ok
         3  C          ok
        24  X          ok
        25  Y          ok
        26  Z          ok
        27  AA         ok
       702  ZZ         ok
       703  AAA        ok
       704  AAB        ok
   2708874  EXCEL      ok
1110829947  COLUMNS    ok

Answer 3

这是一种方法.它是XlsxWriter模块中代码的变体:

def col_to_num(col_str):
    """ Convert base26 column string to number. """
    expn = 0
    col_num = 0
    for char in reversed(col_str):
        col_num += (ord(char) - ord('A') + 1) * (26 ** expn)
        expn += 1

    return col_num


>>> col_to_num('A')
1
>>> col_to_num('AB')
28
>>> col_to_num('ABA')
729
>>> col_to_num('AAB')
704

Answer 4

使用 openpyxl

import openpyxl
(column_string, row) = openpyxl.cell.coordinate_from_string(address)
column = openpyxl.cell.column_index_from_string(column_string) 

Answer 5

安装 openpyxl 模块后，您可以将以下内容添加到控制台：

>>> from openpyxl.utils import get_column_letter, column_index_from_string

>>> get_column_letter(1)
'A'
>>> column_index_from_string('A')
1

只需更改字母和数字即可满足您的需求。