Roo*_*Dev 2 javascript json sequelize.js
我有这个查询:
\n const data = await modelOwners.findAll({\n attributes: ["id", "name", "email"],\n include: [\n {\n model: modelLotsTantiemes,\n as: "LotsOwner",\n attributes: [\n "lotId",\n ["distributionKeyId", 'costKey'],\n [ Sequelize.fn('sum', Sequelize.col("tantiemeNumber")), 'totalTantieme' ],\n ],\n },\n ],\n where: { coproNumber: req.header("customerId")},\n group: ["name", "LotsOwner.distributionKeyId"],\n raw: true,\n nest: false,\n order: [["name", "ASC"]],\n});\nRun Code Online (Sandbox Code Playgroud)\n当我在 Postman Y 上测试它时,结果如下:
\n"data": [\n {\n "id": 4,\n "name": "Clement Tine",\n "email": "clementt@fruitsetlegumes.fr",\n "LotsOwner.field1": 2,\n "LotsOwner.field2": 1,\n "LotsOwner.field3": "1892"\n },\n {\n "id": 6,\n "name": "L\xc3\xa9o Pard",\n "email": "leopard@thoiry.fr",\n "LotsOwner.field1": 9,\n "LotsOwner.field2": 1,\n "LotsOwner.field3": "4432"\n }]\nRun Code Online (Sandbox Code Playgroud)\n但我想要为我的专栏起一个其他名称,例如:
\n"data": [\n {\n "id": 4,\n "name": "Clement Tine",\n "email": "clementt@fruitsetlegumes.fr",\n "field1": 2,\n "field2": 1,\n "field3": "1892"\n }]\n \nRun Code Online (Sandbox Code Playgroud)\n我不想要关联别名的名称。您知道是否有选择可以做到这一点吗?
\n如果您希望关联模型的属性与主模型处于同一级别,那么您需要手动包含它们以指示关联模型名称:
const data = await modelOwners.findAll({
attributes: ["id", "name", "email",
[Sequelize.col('"LotsOwner"."distributionKeyId"'), 'costKey']
],
include: [
{
model: modelLotsTantiemes,
as: "LotsOwner",
...
Run Code Online (Sandbox Code Playgroud)
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