mmu*_*lva 90 java json jackson
我有String以下值:
[
{
"key1": "value11",
"key2": "value12"
},
{
"key1": "value21",
"key2": "value22"
}
]
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以下课程:
public class SomeClass {
private String key1;
private String key2;
/* ... getters and setters omitted ...*/
}
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我想将它解析为a List<SomeClass>或aSomeClass[]
使用杰克逊 这是最简单的方法ObjectMapper吗?
mmu*_*lva 159
我终于明白了:
ObjectMapper objectMapper = new ObjectMapper();
TypeFactory typeFactory = objectMapper.getTypeFactory();
List<SomeClass> someClassList = objectMapper.readValue(jsonString, typeFactory.constructCollectionType(List.class, SomeClass.class));
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Sta*_*Man 80
另一个答案是正确的,但为了完整起见,还有其他方法:
List<SomeClass> list = mapper.readValue(jsonString, new TypeReference<List<SomeClass>>() { });
SomeClass[] array = mapper.readValue(jsonString, SomeClass[].class);
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