objective-c nsmutablearray setValue forKey问题

Question

我的代码:

NSArray *array = //objects here
NSMutableArray *mutarray = [[NSMutableArray alloc] init];

    for (NSString *s in array)
    {
        NSRange ran = [s rangeOfString:@"abc"];
    if (ran.location != NSNotFound)
    {
        int inde = [array indexOfObject:s];
        [mutarray setValue:[NSNumber numberWithInt:inde] forKey:s];
    } 
    }
    NSLog (@"mutarray: %@", mutarray);  

我尝试过NSMutableDictionary,但内容是无序的,所以我更喜欢NSMutableArray有序地存储值和键.但NSLog的输出什么也没有显示,到底是什么？NSMutableDictionary的输出显示了四个发现.

---

编辑:

我甚至在NSLog前面尝试过这段代码,但没有显示:

[mutarray setValue:@"aha" forKey:@"jaha"];

---

编辑:伙计们,谢谢你的回答!现在我明白了.但问题是我将数字存储为值和字符串作为键.我有一个无序的NSMutableDictionary.我还没弄明白我应该怎么订购它.我有我使用的代码,但没有正确编写:

NSInteger intSort(id num1, id num2, void *context)
{
    int v1 = [num1 intValue];
    int v2 = [num2 intValue];
    if (v1 < v2)
        return NSOrderedAscending;
    else if (v1 > v2)
        return NSOrderedDescending;
    else
        return NSOrderedSame;
}   

在其他方法:

NSArray *ordered = [[mutdic allValues] sortedArrayUsingFunction:intSort context:NULL];
NSLog (@" ordered: %@", ordered);

输出仅显示:

2011-08-29 22:36:03.998 scanner2[32359:207]  ordered: (
    1,
    5,
    9,
    16
)

输出应按数字顺序显示:

2011-08-29 22:36:03.992 scanner2[32359:207] mutdic:  5 jam (geologi) en
2011-08-29 22:36:03.993 scanner2[32359:207] mutdic:  9 jax. (geologi)jammen
2011-08-29 22:36:03.994 scanner2[32359:207] mutdic:  1 beta (geologi).
2011-08-29 22:36:03.995 scanner2[32359:207] mutdic: 16 .(geologi),be;ta;

Answer 1

NSMutableArray不存储键/值对,它只存储对象.要将对象添加到数组,请使用该-addObject:方法.

使用数组存储有序的对象列表.在需要查找给定键的对象时使用字典.如果您想要字典键的有序列表,请使用

NSArray* orderedKeys = 
    [[myDictionary allKeys] sortedArrayUsingSelector:@selector(compare:)];

编辑:还有几个选项.

1. 只需存储索引数组,然后在主array字符串中查找值.

   for (NSUInteger i = 0; i < [array count]; ++i)
   {
       NSString* s = [array objectAtIndex:i];
       NSRange ran = [s rangeOfString:@"abc"];
       if (ran.location != NSNotFound)
       {
           [mutarray addObject:[NSNumber numberWithInt:i]];
       } 
   }
   
   for (NSNumber* index in mutarray)
   {
       NSLog(@"Found %@:%@", index, [array objectAtIndex:[index intValue]]);
   }         
   

2. 存储索引和字符串的二维数组:

   for (NSUInteger i = 0; i < [array count]; ++i)
   
   {
       NSString* s = [array objectAtIndex:i];
       NSRange ran = [s rangeOfString:@"abc"];
       if (ran.location != NSNotFound)
       {
           [mutarray addObject:
               [NSArray arrayWithObjects:[NSNumber numberWithInt:i],
                                         s,
                                         nil]]; 
       } 
   }