无法创建JAXBContext创建我的wsdl

Question

我正在尝试为webservices生成我的WSDL,但是我收到此错误:

Note:   ap round: 2
Exception in thread "main" javax.xml.ws.WebServiceException: Unable to create JAXBContext
        at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.createJAXBContext(AbstractSEIModelImpl.java:153)
        at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.postProcess(AbstractSEIModelImpl.java:83)
        at com.sun.xml.internal.ws.model.RuntimeModeler.buildRuntimeModel(RuntimeModeler.java:244)
        at com.sun.tools.internal.ws.wscompile.WsgenTool.buildModel(WsgenTool.java:229)
        at com.sun.tools.internal.ws.wscompile.WsgenTool.run(WsgenTool.java:112)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
        at java.lang.reflect.Method.invoke(Method.java:597)
        at com.sun.tools.internal.ws.Invoker.invoke(Invoker.java:105)
        at com.sun.tools.internal.ws.WsGen.main(WsGen.java:41)
Caused by: java.security.PrivilegedActionException: com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
java.lang.StackTraceElement does not have a no-arg default constructor.
        this problem is related to the following location:
                at java.lang.StackTraceElement
                at public java.lang.StackTraceElement[] java.lang.Throwable.getStackTrace()
                at java.lang.Throwable
                at java.lang.Exception
                at java.sql.SQLException
                at private java.sql.SQLException wsdb.jaxws.SQLExceptionBean.nextException
                at wsdb.jaxws.SQLExceptionBean

        at java.security.AccessController.doPrivileged(Native Method)
        at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.createJAXBContext(AbstractSEIModelImpl.java:140)
        ... 10 more
Caused by: com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
java.lang.StackTraceElement does not have a no-arg default constructor.
        this problem is related to the following location:
                at java.lang.StackTraceElement
                at public java.lang.StackTraceElement[] java.lang.Throwable.getStackTrace()
                at java.lang.Throwable
                at java.lang.Exception
                at java.sql.SQLException
                at private java.sql.SQLException wsdb.jaxws.SQLExceptionBean.nextException
                at wsdb.jaxws.SQLExceptionBean

        at com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:91)
        at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:436)
        at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.(JAXBContextImpl.java:277)
        at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1100)
        at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:143)
        at com.sun.xml.internal.bind.api.JAXBRIContext.newInstance(JAXBRIContext.java:95)
        at com.sun.xml.internal.ws.developer.JAXBContextFactory$1.createJAXBContext(JAXBContextFactory.java:97)
        at com.sun.xml.internal.ws.model.AbstractSEIModelImpl$1.run(AbstractSEIModelImpl.java:148)
        at com.sun.xml.internal.ws.model.AbstractSEIModelImpl$1.run(AbstractSEIModelImpl.java:140)
        ... 12 more

我在互联网上看到了一些关于这一点的讨论,为所有类构建一个构造函数,直到创建另一个xml规范.事实是,没有一个真正的答案或我测试的解决方案不起作用.

我在这里读到了关于这个问题的讨论,但它没有终止,我不知道如何解决.如果有人对此有所了解,我非常感谢能将我加入到严格的方向以避免这种情况.

我在JDK 6和wsgen中使用Debian Squezze,Java 1.6_20,JAX-WS JAX-WS RI 2.1.6来生成wsdl.它做的第一步是正确的,用bean类生成jaxws目录.

Answer 1

Throwable对象(即异常和错误)无法直接传输,因为它们无法序列化为XML(StackTraceElement没有no-arg构造函数,这是JAXB所需的).

您必须使用SOAP错误.看到这个问题.它指向您@WebFault应该放在异常类上的注释.(也可能检查这个和这个)

Answer 2

Domenic D.有正确的答案对我有用,但我想扩展它.

我的Maven项目使用JDK 6构建得很好,但是当我切换到使用JDK 1.7作为我的默认值时,构建就破坏了.通过添加显式的jaxb-impl依赖w /版本,它可以工作,例如:

<plugin>
    <groupId>org.jvnet.jax-ws-commons</groupId>
    <artifactId>jaxws-maven-plugin</artifactId>
    <version>2.1</version>
    <dependencies>
        <dependency>
            <groupId>com.sun.xml.bind</groupId>
            <artifactId>jaxb-impl</artifactId>
            <version>2.2.6</version>
        </dependency>
    </dependencies>
    <executions>
        <execution>
        ...
        </execution>
    </executions>
</plugin>

关于版本:此错误列在https://java.net/jira/browse/JAXB-814.它适用于2.2.4u2,2.2.5,2.3版本

Answer 3

我已经通过将jaxb-impl版本从2.1.9修复到2.2.6解决了这个问题，现在可以正常工作

<dependency>
        <groupId>com.sun.xml.bind</groupId>
        <artifactId>jaxb-impl</artifactId>
        <version>2.2.6</version>
</dependency>

Answer 4

看起来您声明的 API 的一部分包含一个类型，该类型使用 StackTraceElement[ ] 类型的内部字段扩展了类型。

由于 StackTraceElement 没有零参数构造函数，因此 JAXB 无法反序列化此类的实例。

尝试从 SQLExceptionBean 中删除 nextException 字段，或从服务 API 中删除 SQLExceptionBean 类型的参数。