Tes*_*est 3 python dictionary list
我有个问题。我在这些列表中有一个列表myList
,还有一个字典。我想计算该字段是否dataOriginSystem
为空或不存在。不幸的是我得到了错误的结果。if(key_nested == 'dataOriginSystem'): ... else: count =+ 1
原因在于 if 查询。既然我问,这个领域存在吗?如果不是,则将其累加,由于我循环遍历所有嵌套键,因此错误之一就在这里。另外,有没有办法提高效率?
如何查询有多少字段dataOriginSystem
为空或不存在?
count = 0
for element in myList:
for key in element.keys():
if(key == 'metaData'):
for key_nested in element[key].keys():
if(key_nested == 'dataOriginSystem'):
if(key_nested == None):
count += 1
else:
count += 1
print(count)
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myList = [
{'_id': 'orders/213123',
'contactEditor': {'name': 'Max Power',
'phone': '1234567',
'email': 'max@power.com'},
'contactSoldToParty': {'name': 'Max Not',
'phone': '123456789',
'email': 'maxnot@power.com'},
'isCompleteDelivery': False,
'metaData': {'dataOriginSystem': 'Goods',
'dataOriginWasCreatedTime': '10:12:12',},
'orderDate': '2021-02-22',
'orderDateBuyer': '2021-02-22',
},
{'_id': 'orders/12323',
'contactEditor': {'name': 'Max Power2',
'phone': '1234567',
'email': 'max@power.com'},
'contactSoldToParty': {'name': 'Max Not',
'phone': '123456789',
'email': 'maxnot@power.com'},
'isCompleteDelivery': False,
'metaData': {'dataOriginSystem': 'Goods',
'dataOriginWasCreatedTime': '10:12:12',},
'orderDate': '2021-02-22',
'orderDateBuyer': '2021-02-22',
},
{'_id': 'orders/12323',
'contactEditor': {'name': 'Max Power2',
'phone': '1234567',
'email': 'max@power.com'},
'contactSoldToParty': {'name': 'Max Not',
'phone': '123456789',
'email': 'maxnot@power.com'},
'isCompleteDelivery': False,
'metaData': {
'dataOriginWasCreatedTime': '10:12:12',},
'orderDate': '2021-02-22',
'orderDateBuyer': '2021-02-22',
},
{'_id': 'orders/12323',
'contactEditor': {'name': 'Max Power2',
'phone': '1234567',
'email': 'max@power.com'},
'contactSoldToParty': {'name': 'Max Not',
'phone': '123456789',
'email': 'maxnot@power.com'},
'isCompleteDelivery': False,
'metaData': {'dataOriginSystem': None,
'dataOriginWasCreatedTime': '10:12:12',},
'orderDate': '2021-02-22',
'orderDateBuyer': '2021-02-22',
},
]
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结果应该是
[OUT] 2
# Because of the two last elements.
# The first element does not exist
# and the second ist None.
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您可以直接在嵌套键上使用dict.get
,返回默认值None
,然后计算None
获得的值的数量:
sum(d['metaData'].get('dataOriginSystem', None) is None for d in myList)
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输出
2
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