Guz*_*tra 2 authentication laravel laravel-8
我有一个应用程序,我想进行身份验证但不使用用户模型。该模型称为 Karyawan。但是当我更改 auth.php 时,它开始显示此错误:
Illuminate\Auth\EloquentUserProvider::validateCredentials():参数 #1 ($user) 的类型必须为 Illuminate\Contracts\Auth\Authenticatable、App\Models\Karyawan,在 C:\KKP\Project_KKP\vendor\laravel\ 中调用Framework\src\Illuminate\Auth\SessionGuard.php 第 426 行
Laravel 版本为 8
验证文件
'defaults' => [
'guard' => 'web',
'passwords' => 'users',
],
'guards' => [
'web' => [
'driver' => 'session',
'provider' => 'users',
],
],
'providers' => [
'users' => [
'driver' => 'eloquent',
'model' => App\Models\Karyawan::class,
],
],
'passwords' => [
'users' => [
'provider' => 'users',
'table' => 'password_resets',
'expire' => 60,
'throttle' => 60,
],
],
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应用\模型\Karyawan.php
namespace App\Models;
use App\Models\Cuti;
use App\Models\Role;
use App\Models\Divisi;
use App\Models\Jabatan;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Factories\HasFactory;
class Karyawan extends Model
{
use HasFactory;
protected $guarded = ['karyawan_id'];
protected $table = 'karyawans';
public function scopeSearch($query, array $searchs) {
$query->when($searchs['search'] ?? false, function($query, $search) {
return $query->where('nama', 'like', '%' . $search . '%')
->orWhere('divisi', 'like', '%' . $search . '%')
->orWhere('jabatan', 'like', '%' . $search . '%')
->orWhere('agama', 'like', '%' . $search . '%')
->orWhere('nik', 'like', '%' . $search . '%');
});
}
public function role_id()
{
return $this->belongsTo(Role::class);
}
public function divisi()
{
return $this->belongsTo(Divisi::class);
}
public function jabatan()
{
return $this->belongsTo(Jabatan::class);
}
public function cuti()
{
return $this->hasMany(Cuti::class);
}
}
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网页.php
Route::get('/', [BasicLoginController::class, 'login']);
Route::post('/', [BasicLoginController::class, 'authenticate']);
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基本登录控制器.php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;
class BasicLoginController extends Controller
{
public function login()
{
return view ('login.login', [
'title' => 'Login'
]);
}
public function authenticate(Request $request) {
$credentials = $request->validate([
'email' => 'required|email:dns',
'password' => 'required'
]);
if(Auth::attempt($credentials)) {
$request->session()->regenerate();
return redirect()->intended('/dashboard');
}
return back()->with('loginError', 'Email atau Password salah');
}
}
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正如错误所示,您的类需要Illuminate\Contracts\Auth\Authenticatable通过扩展类来实现公共用户模型所做的接口Illuminate\Foundation\Auth\User as Authenticatable;
因此,要么在您的类中实现契约,并在其中声明所有需要的方法功能。
或者
只需扩展现有的Illuminate\Foundation\Auth\User
namespace App\Models;
//...
use Illuminate\Foundation\Auth\User as Authenticatable;
class Karyawan extends Authenticatable
{
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该类Illuminate\Foundation\Auth\User扩展了模型类Illuminate\Database\Eloquent\Model,因此模型功能仍然可用。
编辑:
在这里,复制粘贴这个模型,你应该学习一些PSR,尤其是PSR-4
namespace App\Models;
use App\Models\Cuti;
use App\Models\Role;
use App\Models\Divisi;
use App\Models\Jabatan;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Foundation\Auth\User as Authenticatable;
class Karyawan extends Authenticatable
{
use HasFactory;
protected $guarded = ['karyawan_id'];
protected $table = 'karyawans';
public function scopeSearch($query, array $searchs) {
$query->when($searchs['search'] ?? false, function($query, $search) {
return $query->where('nama', 'like', '%' . $search . '%')
->orWhere('divisi', 'like', '%' . $search . '%')
->orWhere('jabatan', 'like', '%' . $search . '%')
->orWhere('agama', 'like', '%' . $search . '%')
->orWhere('nik', 'like', '%' . $search . '%');
});
}
public function role_id()
{
return $this->belongsTo(Role::class);
}
public function divisi()
{
return $this->belongsTo(Divisi::class);
}
public function jabatan()
{
return $this->belongsTo(Jabatan::class);
}
public function cuti()
{
return $this->hasMany(Cuti::class);
}
}
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