使用 flextable 中的 add_header_row 创建不同宽度的列

Question

我有数据如下：

dat <- structure(list(rn = c("type_A", "type_B", "type_C"
), freq = list(c(0, 0, 0, 5, 7, 16, 28), c(2, 1, 0, 5, 0, 8), 
    c(0, 0, 3, 5, 12, 53, 73)), colspan = list(c(`25` = 1, `100` = 2, 
`250` = 1, `500` = 1, `1000` = 1, Infinity = 3, SUM = 1), c(`25` = 1, 
`100` = 2, `250` = 1, `500` = 1, Infinity = 4, SUM = 1), c(`25` = 1, 
`50` = 1, `100` = 1, `250` = 1, `500` = 1, Infinity = 4, SUM = 1
))), row.names = c(NA, 3L), class = "data.frame")

total_colspan = c(0, 25, 50, 100, 250, 500, 1000, 1500, 3000, "Infinity", "SUM")

      rn                   freq             colspan
1 type_A  0, 0, 0, 5, 7, 16, 28 1, 2, 1, 1, 1, 3, 1
2 type_B       2, 1, 0, 5, 0, 8    1, 2, 1, 1, 4, 1
3 type_C 0, 0, 3, 5, 12, 53, 73 1, 1, 1, 1, 1, 4, 1

我想在 R-markdown Word 文档中创建一个具有不同列跨度的表格（但它们加起来都是10），如下表所示：

有人建议我尝试flextable一下（链接）。我正在尝试使用标头选项来创建这些不同的 colspan。我想过做类似的事情：

dat_table <- flextable(dat)
dat_table <- lapply(dat_table, add_header_row, values = unlist(freq), colwidths = unlist(colspan))

但这是行不通的。

编辑：

我的第二次尝试：

dat <- structure(list(rn = c("type_A", "type_B", "type_C"
), freq = list(c(0, 0, 0, 5, 7, 16, 28), c(2, 1, 0, 5, 0, 8), 
    c(0, 0, 3, 5, 12, 53, 73)), colspan = list(c(1, 2, 1, 1, 1, 3, 1),  c(1, 2, 1, 1, 4, 1), c(1, 1, 1, 1,  1, 4, 1
))), row.names = c(NA, 3L), class = "data.frame")

# The thresholds as in the picture
thresholds <- data.frame(c("Lower threshold","Upper threshold"), c(0,25), c(25,50), c(50,100), c(100,250), c(250,500),c(500,1000),c(1000,1500),c(1500,3000),c(3000, "Infinity"), c("", "SUM"))
names(thresholds) <- c("One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven")
thresholds <- flextable(thresholds)

# There was one column to few in the example
dat <- transform(dat, colspan=Map('c', 1, dat[["colspan"]] ))
dat <- transform(dat, freq=Map('c', "", dat[["freq"]] ))

# for loop to stick to the syntax
for (i in nrow(dat)) {
 thresholds <- add_header_row(thresholds, values = dat[[2]][[i]], colwidths = dat[[3]][[i]])
}

由于某种原因，它只添加一行（虽然它允许添加更多标题）。

Answer 1

这是一个可能太过分的解决方案，但似乎可以满足您的需求：

library(tidyverse)
library(flextable)

dat <- structure(list(rn = c("type_A", "type_B", "type_C"
), freq = list(c(0, 0, 0, 5, 7, 16, 28), c(2, 1, 0, 5, 0, 8), 
               c(0, 0, 3, 5, 12, 53, 73)), colspan = list(c(1, 2, 1, 1, 1, 3, 1),  c(1, 2, 1, 1, 4, 1), c(1, 1, 1, 1,  1, 4, 1
               ))), row.names = c(NA, 3L), class = "data.frame")

# The thresholds as in the picture
thresholds <- data.frame(c("Lower threshold","Upper threshold"), c(0,25), c(25,50), c(50,100), c(100,250), c(250,500),c(500,1000),c(1000,1500),c(1500,3000),c(3000, "Infinity"), c("", "SUM"))
names(thresholds) <- c("One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven")

out <- map(1:nrow(dat), function(index){
  out <- data.frame("freq" = dat$freq[[index]], 
                    "span" = dat$colspan[[index]]) %>% 
    tidyr::uncount(span, .id = 'span') %>% 
    mutate(freq = ifelse(span>1, NA, freq)) %>% 
    t %>% 
    as.data.frame() %>% 
    mutate(rn = dat$rn[[index]],
           across(everything(), ~as.character(.))) %>% 
    select(rn, everything()) %>% 
    set_names(nm = names(thresholds)) %>% 
    slice(1)
  return(out)
}) 

combined <- thresholds %>% 
  mutate(across(everything(),  ~as.character(.))) %>% 
  bind_rows(out) 

spans <- map(1:length(dat$colspan), function(index){
  spans <- dat$colspan[[index]] %>%  
    as_tibble() %>% 
    mutate(idx = row_number()) %>% 
    tidyr::uncount(value, .remove = F) %>% 
    group_by(idx) %>%
    mutate(pos = 1:n(),
           value = ifelse(pos != 1, 0, value)) %>% 
    ungroup() %>% 
    select(value) %>% 
    t
  return(append(1, spans))
})

myft <- flextable(combined) %>% 
  theme_box()

myft$body$spans$rows[3:nrow(myft$body$spans$rows),] <- matrix(unlist(spans), ncol = ncol(combined), byrow = TRUE)

myft

^{由reprex 包(v2.0.1)于 2022-04-29 创建}

这使得该表：