如何在UIPickerView中更改字体大小？

Question

我有一个UIPickerView.这有近200个项目,每个项目都有长文本,因此,我想调整UIPickerView的字体大小.我怎么能改变它？有可能的？谁能帮我？谢谢 !

Yuva.M

Answer 1

您需要pickerView:viewForRow:forComponent:reusingView:在picker的委托中实现方法

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view{
    UILabel* tView = (UILabel*)view;
    if (!tView){
        tView = [[UILabel alloc] init];
            // Setup label properties - frame, font, colors etc
            ...
    }
    // Fill the label text here
    ...
    return tView;
}

Answer 2

在Swift for iOS8中更新,您可以将其添加到您的委托:

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView!) -> UIView {

    var pickerLabel = view as? UILabel;

    if (pickerLabel == nil)
    {
        pickerLabel = UILabel()

        pickerLabel?.font = UIFont(name: "Montserrat", size: 16)
        pickerLabel?.textAlignment = NSTextAlignment.Center
    }

    pickerLabel?.text = fetchLabelForRowNumber(row)

    return pickerLabel!;
}

Answer 3

对于UIPickerView行的字体调整

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{
    UILabel* pickerLabel = (UILabel*)view;

    if (!pickerLabel)
    {
        pickerLabel = [[UILabel alloc] init];

        pickerLabel.font = [UIFont fontWithName:@"SourceSansPro-Semibold"                size:16];

        pickerLabel.textAlignment=NSTextAlignmentCenter;
    }
    [pickerLabel setText:[self.data objectAtIndex:row]];

    return pickerLabel;
}

Answer 4

试试这个,它应该有所帮助:

  - (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view{
UILabel* tView = (UILabel*)view;
if (!tView){
tView = [[UILabel alloc] init];
// Setup label properties - frame, font, colors etc
...
//adjustsFontSizeToFitWidth property to YES
tView.minimumFontSize = 8.;
tView.adjustsFontSizeToFitWidth = YES;
}
// Fill the label text here
...
return tView;
}


// altro modo completo sembrerebbe...
- (UIView *)pickerView:(UIPickerView *)pickerView
viewForRow:(NSInteger)row
forComponent:(NSInteger)component
reusingView:(UIView *)view {

UILabel *pickerLabel = (UILabel *)view;

if (pickerLabel == nil) {
CGRect frame = CGRectMake(0.0, 0.0, 80, 32);
pickerLabel = [[[UILabel alloc] initWithFrame:frame] autorelease];
[pickerLabel setTextAlignment:UITextAlignmentLeft];
[pickerLabel setBackgroundColor:[UIColor clearColor]];
[pickerLabel setFont:[UIFont boldSystemFontOfSize:15]];
}

[pickerLabel setText:[pickerDataArray objectAtIndex:row]];

return pickerLabel;

}

Answer 5

Swift 4: 更新@Alessandro Ornano回答并避免Force_cast违规错误:

func pickerView(_ pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusing view: UIView?) -> UIView {
    var label = UILabel()
    if let v = view as? UILabel { label = v }
    label.font = UIFont (name: "Helvetica Neue", size: 10)
    label.text =  dataArray[row]
    label.textAlignment = .center
    return label
}

Answer 6

斯威夫特3 | 自动收缩

设置adjustsFontSizeToFitWidth=true和minimumScaleFactor=0.5

func pickerView(_ pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusing view: UIView?) -> UIView {

    var label: UILabel
    if let view = view as? UILabel { label = view }
    else { label = UILabel() }

    label.text = "My Picker Text"
    label.textAlignment = .center
    label.font = UIFont.boldSystemFont(ofSize: 20)
    label.adjustsFontSizeToFitWidth = true
    label.minimumScaleFactor = 0.5

    return label
}

Answer 7

斯威夫特 4.x

func pickerView(_ pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusing view: UIView?) -> UIView {
        var label = UILabel()
        if let v = view {
            label = v as! UILabel
        }
        label.font = UIFont (name: "Helvetica Neue", size: 10)
        label.text =  dataArray[row]
        label.textAlignment = .center
        return label
    }