如何动态改变形状颜色？

Question

我有

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
   android:shape="rectangle">
    <solid
       android:color="#FFFF00" />
    <padding android:left="7dp"
        android:top="7dp"
        android:right="7dp"
        android:bottom="7dp" />
</shape>

<TextView
    android:background="@drawable/test"
    android:layout_height="45dp"
    android:layout_width="100dp"
    android:text="Moderate"
/>

所以现在我希望这个形状根据我从Web服务调用中获取的信息来改变颜色.所以它可能是黄色或绿色或红色或其他任何取决于我从网络电话呼叫收到的颜色.

如何更改形状的颜色？根据这些信息？

Answer 1

您可以像这样修改它

GradientDrawable bgShape = (GradientDrawable)btn.getBackground();
bgShape.setColor(Color.BLACK);

Answer 2

对我来说,它崩溃了,因为getBackground返回了一个GradientDrawable而不是一个ShapeDrawable.

所以我修改它像这样:

((GradientDrawable)someView.getBackground()).setColor(someColor);

Answer 3

这适用于我,使用初始xml资源:

example.setBackgroundResource(R.drawable.myshape);
GradientDrawable gd = (GradientDrawable) example.getBackground().getCurrent();
gd.setColor(Color.parseColor("#000000"));
gd.setCornerRadii(new float[]{30, 30, 30, 30, 0, 0, 30, 30});
gd.setStroke(2, Color.parseColor("#00FFFF"), 5, 6);

上述结果:http://i.stack.imgur.com/hKUR7.png

Answer 4

您可以使用Java构建自己的形状.我为像Page Controler这样的iPhone做了这个,并用Java绘制形状:

/**
 * Builds the active and inactive shapes / drawables for the page control
 */
private void makeShapes() {

    activeDrawable = new ShapeDrawable();
    inactiveDrawable = new ShapeDrawable();
    activeDrawable.setBounds(0, 0, (int) mIndicatorSize,
            (int) mIndicatorSize);
    inactiveDrawable.setBounds(0, 0, (int) mIndicatorSize,
            (int) mIndicatorSize);

    int i[] = new int[2];
    i[0] = android.R.attr.textColorSecondary;
    i[1] = android.R.attr.textColorSecondaryInverse;
    TypedArray a = this.getTheme().obtainStyledAttributes(i);

    Shape s1 = new OvalShape();
    s1.resize(mIndicatorSize, mIndicatorSize);
    Shape s2 = new OvalShape();
    s2.resize(mIndicatorSize, mIndicatorSize);

    ((ShapeDrawable) activeDrawable).getPaint().setColor(
            a.getColor(0, Color.DKGRAY));
    ((ShapeDrawable) inactiveDrawable).getPaint().setColor(
            a.getColor(1, Color.LTGRAY));

    ((ShapeDrawable) activeDrawable).setShape(s1);
    ((ShapeDrawable) inactiveDrawable).setShape(s2);
}

希望这可以帮助.Greez Fabian

Answer 5

    LayerDrawable bgDrawable = (LayerDrawable) button.getBackground();
    final GradientDrawable shape = (GradientDrawable)
            bgDrawable.findDrawableByLayerId(R.id.round_button_shape);
    shape.setColor(Color.BLACK);

Answer 6

也许其他人需要在XML中改变颜色而不需要像我需要的那样创建多个drawable.然后创建一个没有颜色的圆形绘图,然后为ImageView指定backgroundTint.

circle.xml

<?xml version="1.0" encoding="utf-8"?>
<shape
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
</shape>

在你的布局中:

<ImageView
    android:layout_width="50dp"
    android:layout_height="50dp"
    android:background="@drawable/circle"
    android:backgroundTint="@color/red"/>

编辑:

有一个关于此方法的错误,阻止它在Android Lollipop 5.0(API级别21)上运行.但已在新版本中修复.

Answer 7

circle.xml(drawable)

<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">

<solid
    android:color="#000"/>

<size
    android:width="10dp"
    android:height="10dp"/>
</shape>

布局

<ImageView
      android:id="@+id/circleColor"
      android:layout_width="15dp"
       android:layout_height="15dp"
      android:textSize="12dp"
       android:layout_gravity="center"
       android:layout_marginLeft="10dp"
      android:background="@drawable/circle"/>

在活动中

   circleColor = (ImageView) view.findViewById(R.id.circleColor);
   int color = Color.parseColor("#00FFFF");
   ((GradientDrawable)circleColor.getBackground()).setColor(color);