如何让UILabel响应水龙头？

Question

我发现我可以比UITextField更快地创建UILabel,并且我计划在大多数时间使用UILabel作为我的数据显示应用程序.

总而言之,我希望让用户点击UILabel并让我的回调响应.那可能吗？

谢谢.

Answer 1

您可以UITapGestureRecognizer向UILabel 添加实例.

例如:

UITapGestureRecognizer *tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(labelTapped)];
tapGestureRecognizer.numberOfTapsRequired = 1;
[myLabel addGestureRecognizer:tapGestureRecognizer];
myLabel.userInteractionEnabled = YES;

Answer 2

如果您正在使用故事板,则可以在故事板中执行此整个过程而无需其他代码.在故事板上添加标签,然后在标签上添加一个点按手势.在"实用工具"窗格中,确保选中"已启用用户交互"标签.从点击手势(在故事板中视图控制器的底部),按住Ctrl键并单击并拖动到ViewController.h文件并创建一个Action.然后在ViewController.m文件中实现该操作.

Answer 3

Swift 3.0

初始化手势 tempLabel

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action: #selector(self.actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

Swift 4.0

初始化手势 tempLabel

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action:@selector(actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

Answer 4

Swift 2.0:

我正在添加一个nsmutable字符串作为sampleLabel的文本,启用用户交互,添加点击手势并触发方法.

override func viewDidLoad() {
    super.viewDidLoad()

    let newsString: NSMutableAttributedString = NSMutableAttributedString(string: "Tap here to read the latest Football News.")
    newsString.addAttributes([NSUnderlineStyleAttributeName: NSUnderlineStyle.StyleDouble.rawValue], range: NSMakeRange(4, 4))
    sampleLabel.attributedText = newsString.copy() as? NSAttributedString

    let tapGesture: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "tapResponse:")
    tapGesture.numberOfTapsRequired = 1
    sampleLabel.userInteractionEnabled =  true
    sampleLabel.addGestureRecognizer(tapGesture)

}
func tapResponse(recognizer: UITapGestureRecognizer) {
    print("tap")
}