如何查询满足谓词的相关记录数的最大值

Dan*_*ien 3 python django django-models django-aggregation

我正在开发一个Django应用程序,遇到了我想评估的棘手汇总查询。

demo我的项目的应用程序中,我声明了以下用于代表图书馆馆藏的模型类:

from django.db import models

class Book(models.Model):
    interesting = models.BooleanField()

class Library(models.Model):
    books = models.ManyToManyField(Book)
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我想查询的是单个图书馆中“有趣”图书的最大数量,这是每个图书馆中“有趣”图书的最大数量。

在SQL中,这是:

select max(a.num_interesting_books) as max
from (select count(demo_book.id) as num_interesting_books
      from demo_book
      inner join demo_library_books on (demo_book.id = demo_library_books.book_id)
      where demo_book.interesting=TRUE
      group by demo_library_books.library_id) as a
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使用以下测试数据:

insert into demo_library(id) values (1), (2), (3);
insert into demo_book(id, interesting) values
(1, FALSE), (2, FALSE), (3, TRUE),
(4, TRUE), (5, TRUE),
(6, TRUE), (7, TRUE), (8, TRUE), (9, FALSE);
insert into demo_library_books(library_id, book_id) values
(1, 1), (1, 2), (1, 3),
(2, 4), (2, 5),
(3, 6), (3, 7), (3, 8), (3, 9), (3, 3);
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上面的SELECT语句导致:

 max
-----
   4
(1 row)
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如预期的那样。

是否可以使用Django的查询API来计算此值?

Dan*_*ien 5

我想我知道了:

Library.objects.filter(books__interesting=True).annotate(num_interesting_books=Count('pk')).aggregate(max=Max('num_interesting_books'))
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转换为SQL,这是:

select max(a.num_interesting_books) as max
from (select demo_library.*, count(demo_library.id) as num_interesting_books
      from demo_library
      inner join demo_library_books on (demo_library.id = demo_library_books.library_id)
      inner join demo_book on (demo_library_books.book_id = demo_book.id)
      where demo_book.interesting=TRUE
      group by demo_library.id) as a
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