删除 .com python 之后的所有内容

Question

我在 urls.tmp 文件中得到了包含 3 个 url 的文件：

https://site1.com.br/wp-content/uploads/2020/06/?SD
https://site2.com.br/wp-content/uploads/tp-datademo/home-4/data/tp-hotel-booking/?SD
https://site3.com.br/wp-content/uploads/revslider/hotel-home/?MD

我想删除每个“com.br/”之后的所有内容。

我尝试了这段代码：

# open the file
sys.stdout = open("urls.tmp", "w")

# start remove
for i in "urls.tmp":
    url_parts = urllib.parse.urlparse(i)
    result = '{uri.scheme}://{uri.netloc}/'.format(uri=url_parts)
    print(result) #overwrite the file

# close the file
sys.stdout.close()

但输出给了我这个奇怪的东西：

:///
:///
:///
:///
:///
:///
:///
:///

我是初学者，我做错了什么？

Answer 1

您正在迭代"urls.tmp"字符串本身，但想要逐行遍历打开的文件对象。

所以试试这个：

with open("urls.tmp", "r") as urls_file:
    for line in urls_file:
        url_parts = urllib.parse.urlparse(line)
        result = "{uri.scheme}://{uri.netloc}/".format(uri=url_parts)
        print(result)

编辑：作者更新了原始问题，提到应使用处理后的网址重写源文件内容，示例如下：

new_urls = []

with open("urls.tmp", "r") as urls_file:
    old_urls = urls_file.readlines()

for line in old_urls:
    url_parts = urllib.parse.urlparse(line)
    proc_url = "{uri.scheme}://{uri.netloc}/\n".format(uri=url_parts)
    new_urls.append(proc_url)

with open("urls.tmp", "w") as urls_file:
    urls_file.writelines(new_urls)