用于解析url PHP的正则表达式

San*_*rst 1 php regex url

我需要查找给定的URL是否有效,如果它包含url haviing,则应该允许它

1.通用顶级域名2.国家代码顶级域名请参阅以下网址 http://en.wikipedia.org/wiki/List_of_Internet_top-level_domains

我需要在PHP中执行此操作,这是我正在做的事情

    $regexUrl = "((https?|ftp)\:\/\/)?"; // SCHEME 
    $regexUrl .= "([a-zA-Z0-9+!*(),;?&=\$_.-]+(\:[a-zA-Z0-9+!*(),;?&=\$_.-]+)?@)?"; // User and Pass 
    $regexUrl .= "([a-zA-Z0-9-]+)\.([a-zA-Z]{2,3})";  // Host or IP 
    $regexUrl .= "(\:[0-9]{2,5})?"; // Port 
    $regexUrl .= "(\/([a-zA-Z0-9+\$_-]\.?)+)*\/?"; // Path 
    $regexUrl .= "(\?[a-zA-Z+&\$_.-][a-zA-Z0-9;:@&%=+\/\$_.-]*)?"; // GET Query 
    $regexUrl .= "(#[a-zA-Z_.-][a-zA-Z0-9+\$_.-]*)?"; // Anchor 
    //if(preg_match_all("#\bhttps?://[^\s()]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#", $message, $matches1, PREG_PATTERN_ORDER))
    //$pattern = '/((https?|ftp)\:(\/\/)|(file\:\/{2,3}))?(((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))|(((([a-zA-Z0-9]+)(\.)?)+)(\.)(com|org|net|gov|mil|biz|info|mobi|name|aero|jobs|museum|[a-z]{2}))([\/][\/a-zA-Z0-9\.]*)*([\/]?(([\?][a-zA-Z0-9]+[\=][a-zA-Z0-9\%\(\)]*)([\&][a-zA-Z0-9]+[\=][a-zA-Z0-9\%\(\)]*)*))?/';
    if(preg_match_all("/$regexUrl/", $urlMessage, $matches1, PREG_PATTERN_ORDER))
    {
      try
        {
            foreach($matches1[0] as $urlToTrim1)
            {
                $url= $urlToTrim1;
                echo $url;
            }
        }
        catch(Exception $e)
        {
            $url="-1";
        }
    }

dec*_*eze 6

要弄清楚它是否通常是有效的URL:

filter_var($url, FILTER_VALIDATE_URL)
Run Code Online (Sandbox Code Playgroud)

http://www.php.net/manual/en/function.filter-var.php

如果您想确认TLD在您的批准列表中(我不知道是否filter_var到目前为止检查TLD是否确实存在):

$host = parse_url($url, PHP_URL_HOST);
$tld = substr($host, strrpos($host, '.') + 1);

// check if $tld is in a list of allowed TLDs
Run Code Online (Sandbox Code Playgroud)

或者只是尝试使用查找域的DNS记录gethostbyname.如果存在,则它是有效域.*


*除非你被DNS欺骗,否则如果这种情况对你很重要......