2个向量之间的度数？

Question

这个学位计算有什么问题？

我选择了2个矢量,它们的度数应该是90°.

我用cos,cos ^ -1尝试了它,没有cos计算.但是我的代码的输出是:
0(没有cos计算)
1(cosinus)
1.5707963267949(cosinus ^ -1(acos))

local square = math.sqrt;
local weaponVector, hitVector = , {x = 0, y = 0, z = 1,}, {x = 0, y = 1, z = 0,};
local xW, yW, zW = weaponVector.x, weaponVector.y, weaponVector.z;
local xH, yH, zH = hitVector.x, hitVector.y, hitVector.z;
local angleBetweenWeaponAndHitDirection = math.acos(math.abs(xW*xH+yW*yH+zW*zH)
            / (square(xW*xW+yW*yW+zW*zW) * square(xH*xH+yH*yH+zH*zH)));
if (angleBetweenWeaponAndHitDirection>180) then
    angleBetweenWeaponAndHitDirection = 360-angleBetweenWeaponAndHitDirection;
end
print(angleBetweenWeaponAndHitDirection)
print(math.cos(angleBetweenWeaponAndHitDirection))
print(math.acos(angleBetweenWeaponAndHitDirection))

Answer 1

1.57079是正确答案,但在Radians中.

要将弧度转换为度数,请乘以180/pi.