无效参数：隔离消息中的非法参数：（对象是aReceivePort）

Question

我不确定我在这段代码中是否做错了什么，但我在生成新隔离时显然传递了 SendPort，但是当我调用时： Infrastructure.instance.initialize();我收到以下异常：

Invalid argument(s): Illegal argument in isolate message: (object is aReceivePort)

这是基本实现Infrastructure：

class Infrastructure {
  late final SendPort _sendPort;
  late final ReceivePort _receivePort; 

  Infrastructure._() {
    _receivePort = ReceivePort();
    Isolate.spawn(_processWorkItemsInBackground, _receivePort.sendPort,
        debugName: 'InfrastructureIsolate');

    _sendPort = _receivePort.first as SendPort;
  }

  Future<void> dispose() async {
    // Send a signal to the spawned isolate indicating that it should exit:
    _sendPort.send(null);
  }

  static final Infrastructure instance = Infrastructure._();

  void initialize() {}

  Future<void> _processWorkItemsInBackground(SendPort sendPort) async {
    ModuleLogger.moduleLogger.info('Infrastructure isolate started.');

    // Send a SendPort to the main isolate
    // so that it can send JSON strings to this isolate:
    final commandPort = ReceivePort();
    sendPort.send(commandPort.sendPort);

    // Wait for messages from the main isolate.
    await for (final message in commandPort) {
      // cast the message to one of the expected message types,
      // handle it properly, compile a response and send it back via
      // the sendPort if needed.
      // For example,
      if (message is String) {
        // Read and decode the file.
        final contents = await File(message).readAsString();

        // Send the result to the main isolate.
        sendPort.send(jsonDecode(contents));
      } else if (message == null) {
        // Exit if the main isolate sends a null message, indicating there are no
        // more files to read and parse.
        break;
      }
    }

    ModuleLogger.moduleLogger.info('Infrastructure isolate finished.');
    Isolate.exit();
  }
}

Answer 1

实际上，大约一个月前我就类似问题开了一张票：

https://github.com/dart-lang/sdk/issues/47981

原来这里已经有票了：

https://github.com/dart-lang/sdk/issues/36983

我相信这里发生的事情是因为_processWorkItemsInBackground不是顶级函数，所以它关闭了范围内的所有变量，其中包括此声明late final ReceivePort _receivePort;。因此，当您使用它生成隔离时，_processWorkItemsInBackground隐式尝试将范围内的所有内容发送到隔离，但ReceivePort不允许将 s 发送到隔离，从而导致错误。