如何让 proguard 保留对象的 kotlinx 序列化器?

Noa*_*man 4 proguard kotlinx.serialization

我有一个 kotlin 类和一个对象


@Serializable
@SerialName("Cl")
class Cl(...)

@Serializable
@SerialName("Obj")
object Obj
Run Code Online (Sandbox Code Playgroud)

我的混淆器配置如下

-keepclassmembers class kotlinx.serialization.json.** {
    *** Companion;
}
-keepclasseswithmembers class kotlinx.serialization.json.** {
    kotlinx.serialization.KSerializer serializer(...);
}
-keepclasseswithmembers class .** {
    kotlinx.serialization.KSerializer serializer(...);
}

-keep,includedescriptorclasses class my.package.**$$serializer { *; }
Run Code Online (Sandbox Code Playgroud)

但是,虽然保留了类的序列化程序,但对象的序列化程序却没有保留。这是类的映射:

Cl -> Cl:
...
    ...
    67:67:void <init>(... ,kotlinx.serialization.internal.SerializationConstructorMarker) -> <init>
    70:75:void <init>(...) -> <init>
    67:67:void write$Self(Cl,kotlinx.serialization.encoding.CompositeEncoder,kotlinx.serialization.descriptors.SerialDescriptor) -> e
Cl$$serializer -> Cl$$serializer:
...
    67:75:void <clinit>() -> <clinit>
    67:67:void <init>() -> <init>
    67:67:kotlinx.serialization.KSerializer[] childSerializers() -> childSerializers
    67:67:Cl deserialize(kotlinx.serialization.encoding.Decoder) -> deserialize
    67:67:java.lang.Object deserialize(kotlinx.serialization.encoding.Decoder) -> deserialize
    67:67:void serialize(kotlinx.serialization.encoding.Encoder,Cl) -> serialize
    67:67:void serialize(kotlinx.serialization.encoding.Encoder,java.lang.Object) -> serialize
    67:67:kotlinx.serialization.KSerializer[] typeParametersSerializers() -> typeParametersSerializers
Cl$Companion -> Cl$Companion:
...
    67:67:void <init>() -> <init>
    67:67:kotlinx.serialization.KSerializer serializer() -> serializer
Run Code Online (Sandbox Code Playgroud)

这是对象的映射:

Obj -> Obj:
...
    Obj INSTANCE -> n
    kotlin.Lazy $cachedSerializer$delegate -> o
    ...
    47:47:kotlin.Lazy get$cachedSerializer$delegate() -> e
    47:47:kotlinx.serialization.KSerializer serializer() -> serializer
Obj$$cachedSerializer$delegate$1 -> Obj$a:
...
    Obj$$cachedSerializer$delegate$1 INSTANCE -> l
    47:47:kotlinx.serialization.KSerializer invoke() -> a
    47:47:java.lang.Object invoke() -> m
...
Run Code Online (Sandbox Code Playgroud)

使用以下内容时,这种混淆会导致崩溃(仅当混淆时,仅适用于对象):

-keepclassmembers class kotlinx.serialization.json.** {
    *** Companion;
}
-keepclasseswithmembers class kotlinx.serialization.json.** {
    kotlinx.serialization.KSerializer serializer(...);
}
-keepclasseswithmembers class .** {
    kotlinx.serialization.KSerializer serializer(...);
}

-keep,includedescriptorclasses class my.package.**$$serializer { *; }
Run Code Online (Sandbox Code Playgroud)

Serializer for class 'Obj' is not found. Mark the class as @Serializable or provide the serializer explicitly.

我如何告诉 Proguard 将序列化器保留为objects?

Ste*_*ris 5

关于如何配置 ProGuard 的可用文档,该文档似乎与您正在使用的配置不匹配。

使用它,你就可以开始了。

纯粹是提供信息,因为上面已经回答了您的问题:运行时的序列化器查找object是不同的,并且通过INSTANCE. 文档中的相关部分。

# Keep `INSTANCE.serializer()` of serializable objects.
-if @kotlinx.serialization.Serializable class ** {
    public static ** INSTANCE;
}
-keepclassmembers class <1> {
    public static <1> INSTANCE;
    kotlinx.serialization.KSerializer serializer(...);
}
Run Code Online (Sandbox Code Playgroud)