使用javascript数组删除li标签

Question

我正在寻找解决方案来删除<li>使用javascript数组过滤的标签.

阵:

var mygroups=["1","8","3","4","5"]

示例(输入):

<li><div>1 element.</div></li>
<li><div>2 element. This is my <span>post</span> into new group</div></li>
<li><div>3 element. Another one</li>
<li><div>
         <a href="javascript:void(0);">Actor</a>
         <a href="/groups/viewgroup/1-first-group">First group</a>
    </div>
</li>
<li><div><a href="javascript:void(0);">Actor</a>
         <a href="/groups/viewgroup/10-ten-group">Ten group</a>5 element. This is my <span>new post</span></div></li>
<li>
   <div>6 element. <a href="/j1.5/index.php/jomsocial/63-zzz/profile">Actor</a></div>
   <div><a href="/groups/viewgroup/test/5-second-group">Group other</a></div>
</li>
<li>7 element.</li>
<li><div><a href="/groups/viewgroup/test/8-second-group">First group</a></div></li>
<li><div><a href="/groups/viewgroup/16-other-group">First group</a></div></li>
<li><div><a href="/j1.5/index.php?option=com_community&view=groups&task=viewgroup&groupid=1&Itemid=4">My other group </a></div></li>

如何获取此输出(删除锚点中不包含数组中的组的所有实例):

<li><div>
         <a href="javascript:void(0);">Actor</a>
         <a href="/groups/viewgroup/1-first-group">First group</a>
    </div>
</li>
<li>
   <div>6 element. <a href="/j1.5/index.php/jomsocial/63-zzz/profile">Actor</a></div>
   <div><a href="/groups/viewgroup/test/5-second-group">Group other</a></div>
</li>
<li><div><a href="/groups/viewgroup/test/8-second-group">First group</a></div></li>
<li><div><a href="/j1.5/index.php?option=com_community&view=groups&task=viewgroup&groupid=4&Itemid=4">My other group </a></div></li>

此代码无效:

    $('li').filter(function() {
    var a = $(this).find('a');
    if (!a.length)
        return true;

    var text = a.attr('href').split('/')[3];
    text = text.substring(0, text.indexOf('-'));
    if ($.inArray(text , mygroups) >= 0)
        return false;

    return true;
}).remove();

这个人既不做这个工作:

 $('li').filter(function() {
    if($(this).is('*:has(a[href|=/group/viewgroup/])') {
        var href = $(this).find('a').attr('href'),
            trail = href.split('/')[3],
            number = + /(\d+)-/.exec(trail)[1];
        return $.inArray(myarray, +number) == -1;
    }
    return true;
}).remove();

Answer 1

使用过滤功能怎么样。

在这种情况下，您选择所有li并筛选出所需的。

$('li').filter(function(index){
    if(/*condition applied*/){
        ....
    }
});