6 javascript unit-testing node.js jestjs nestjs
我正在尝试模拟 bcrypt 哈希方法实现,但出现以下错误:
Error: thrown: "Exceeded timeout of 5000 ms for a test.
Use jest.setTimeout(newTimeout) to increase the timeout value, if this is a long-running test."
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我尝试将超时增加到 30000。此外,我还尝试模拟整个 bcrypt 模块,例如 jest.mock('bcrypt')。我是测试新手,可能存在一些逻辑错误或不良做法。如果您指出它们,我将不胜感激。
我的代码:
import { UserService } from '../user.service';
import { Test, TestingModule } from '@nestjs/testing';
import { Repository } from 'typeorm';
import { getRepositoryToken } from '@nestjs/typeorm';
import * as bcrypt from 'bcrypt';
import { UserEntity } from '../user.entity';
import { UserRepository } from '../user.repository';
import { CreateUserDto } from '../dto/create-user.dto';
import { userStub } from './stubs/user.stub';
describe('UserService', () => {
let userService: UserService;
let userRepository: Repository<UserEntity>;
beforeAll(async () => {
const module: TestingModule = await Test.createTestingModule({
providers: [
UserService,
{
provide: getRepositoryToken(UserRepository),
useClass: Repository,
},
],
}).compile();
userService = module.get<UserService>(UserService);
userRepository = module.get<Repository<UserEntity>>(
getRepositoryToken(UserRepository),
);
});
it('should define UserService', () => {
expect(userService).toBeDefined();
});
it('should define userRepository', () => {
expect(userRepository).toBeDefined();
});
describe('createUser method', () => {
it('has called with valid data', async () => {
const createUserDto: CreateUserDto = {
email: userStub().email,
firstName: userStub().firstName,
lastName: userStub().lastName,
password: userStub().password,
};
const user: UserEntity = userStub();
const spiedBcryptHashMethod = jest
.spyOn(bcrypt, 'hash')
.mockImplementation(() => Promise.resolve(''));
const spiedRepositoryCreateMethod = jest
.spyOn(userRepository, 'create')
.mockReturnValue(user);
const spiedRepositorySaveMethod = jest
.spyOn(userRepository, 'save')
.mockResolvedValue(user);
const createUserResult = await userService.createUser(createUserDto);
expect(spiedBcryptHashMethod).toHaveBeenCalled();
expect(spiedRepositoryCreateMethod).toHaveBeenCalled();
expect(spiedRepositorySaveMethod).toHaveBeenCalledWith(user);
expect(createUserResult).toEqual(user);
});
});
});
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这里出现错误:
const spiedBcryptHashMethod = jest
.spyOn(bcrypt, 'hash')
.mockImplementation(() => Promise.resolve(''));
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我的用户服务代码:
import { Injectable } from '@nestjs/common';
import { InjectRepository } from '@nestjs/typeorm';
import * as bcrypt from 'bcrypt';
import { UserRepository } from './user.repository';
import { CreateUserDto } from './dto/create-user.dto';
import { UserEntity } from './user.entity';
@Injectable()
export class UserService {
constructor(
@InjectRepository(UserRepository) private userRepository: UserRepository,
) {}
public async createUser(createUserDto: CreateUserDto): Promise<UserEntity> {
return await this.userRepository.save(
this.userRepository.create({
...createUserDto,
password: await new Promise((resolve, reject) => {
bcrypt.hash(createUserDto.password, 10, (err, encrypted) => {
if (err) {
reject(err);
}
resolve(encrypted);
});
}).then((onFilled: string) => onFilled),
}),
);
}
}
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好的,关于您的服务代码有很多话要说......
您遇到的直接问题是因为您正在模拟 bcrypt 的hash方法来返回承诺,但使用该方法,因为它返回回调。如果您想继续使用回调与承诺方法混合,您需要执行类似的操作
jest.spyOn(bcrypt, 'hash').mockImplementation((pass, salt, cb) => cb(null, ''))
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这基本上与Promise.resolve('').
不过我不建议这样做。Bcrypt 内置了 Promise 支持,因此您不必用自己的 Promise 包装回调,而是可以这样做,await bcrypt.hash(pass, salt)您将得到散列密码,然后您Promise.resolve('')也将按照您的预期工作。我认为两者都没有必要then((onFullfilled: string) => onFullfilled),但如果您无论如何删除自定义承诺,这种情况就会消失。
一般来说,尝试坚持使用单一异步方法。所有回调(不再建议),所有承诺(更好),或所有异步/等待(现在几乎是标准)。
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