有没有办法从这些字符串中获取日期?我只想隔离年份(例如,2019、2020、2021)
例如:USP_0318 2019 _H13
一个 tidyr 友好的答案将是理想的。
date <- c("USP_03182019_H13","DED_03212019_H1","EL_03202019_H8","EL_10082020_H6","DSP_05122021_H5")
# date
#1 USP_03182019_H13
#2 DED_03212019_H1
#3 EL_03202019_H8
#4 EL_10082020_H6
#5 DSP_05122021_H5
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library(lubridate)
year(mdy(parse_number(date)))
[1] 2019 2019 2019 2020 2021
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或者
sub('.*(\\d{4})_.*', '\\1', date)
[1] "2019" "2019" "2019" "2020" "2021"
stringr::str_extract(date, '\\d{4}(?=_)')
[1] "2019" "2019" "2019" "2020" "2021"
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