在 `try` 内发生错误，未由 `catch` 处理

Question

我希望块内抛出的特定错误try不被处理catch(err)

例子：

const someFunc = async () => {
  ...
  try {
    ...
    // This error should not be handled by the catch and go straight to the middleware
    throw {
      status: 404,
      message: "Not Found",
    };
  } catch (error) {
    throw {
      status: 500,
      message: "Something went wrong",
      reason: error,
    };
  }
};

之后中间件处理错误。

export const errorHandler: ErrorRequestHandler = (err, req, res, next) => {
  const { status = 500, message, reason } = err;
  res.status(status).json({
    success: false,
    message: message || "Something went wrong",
    reason: reason || undefined,
  });
};

Answer 1

如果您在 -block 中抛出错误try，catch则会捕获它。您能做的最好的事情就是检查catch-block 是否抛出了您不想捕获的错误，如果是，则重新抛出它。

const someFunc = async () => {
  try {
    throw {
      status: 404,
      message: "Not Found",
    };
  } catch (error) {
    // If a 404 error is caught, rethrow it.
    if (error.status === 404) {
      throw error;
    }

    throw {
      status: 500,
      message: "Something went wrong",
      reason: error,
    };
  }
};