如何在Objective-C中创建一个字符串或浮点数组

Des*_*ond 5 iphone xcode objective-c ios

我需要一些帮助,我需要知道如何创建从数组中检索的字符串数组.我正在使用powerplot图表,它只接受浮点数或字符串数​​组.

我需要动态地创建这样的东西.

的NSString*sourceData [7] = {@ "2",@ "1",@ "4",@ "8",@ "14",@ "15",@ "10"};

下面是我的代码,以找出字符串中的数字.

NSInteger drunked = [appDelegate.drinksOnDayArray count];
NSMutableArray * dayArray = [[NSMutableArray alloc] init];
NSMutableArray * sdArray = [[NSMutableArray alloc] init];
//float *sdArray[7];


for (int i=0; i<drunked; i++) {
    DayOfDrinks *drinksOnDay = [appDelegate.drinksOnDayArray objectAtIndex:i];
    NSString * dayString= [NSDate stringForDisplayFromDateForChart:drinksOnDay.dateConsumed];
    [dayArray addObject:dayString];
    NSLog(@"%@",[dayArray objectAtIndex:i]);

    drinksOnDay.isDetailViewHydrated = NO;
    [drinksOnDay hydrateDetailViewData];

    NSString * sdString= [NSString stringWithFormat:@"%@", drinksOnDay.standardDrinks];
    [sdArray addObject:sdString];

    NSString *tempstring;
    NSLog(@"%@",[sdArray objectAtIndex:i]);

}
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谢谢您的帮助 :)

Fai*_* S. 7

Objectice-C中的数组并不难以使用:

NSMutableArray *myArray = [NSMutableArray array];
[myArray addObject:@"first string"]; // same with float values
[myArray addObject:@"second string"];
[myArray addObject:@"third string"];
int i;
int count;
for (i = 0, count = [myArray count]; i < count; i = i + 1)
{
   NSString *element = [myArray objectAtIndex:i];
   NSLog(@"The element at index %d in the array is: %@", i, element); // just replace the %@ by %d
}
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您可以使用NSArrayNSMutableArray- 根据您的需要,它们提供不同的功能.

以下教程涵盖了您正在关注的内容:

http://www.cocoalab.com/?q=node/19