Oracle PL/SQL:如何获取堆栈跟踪,包名称和过程名称

Question

有时异常返回类似于:"ORA-06502:PL/SQL:数字或值错误:字符串缓冲区太小".

它不是那么可读,因为它既没有报告表,也没有报告它试图写的值.

在异常发生或被捕获时获取当前过程名称会很有用.

我怎么能得到它？

Answer 1

你可能想要DBMS_UTILITY.FORMAT_ERROR_BACKTRACE功能

SQL> ed
Wrote file afiedt.buf

  1  create or replace procedure p1
  2  is
  3  begin
  4    raise_application_error( -20001, 'Error 1', true );
  5* end;
SQL> /

Procedure created.

SQL> create or replace procedure p2
  2  as
  3  begin
  4    null;
  5    p1;
  6  end;
  7  /

Procedure created.

SQL> begin
  2    p2;
  3  exception
  4    when others then
  5      dbms_output.put_line( dbms_utility.format_error_backtrace );
  6  end;
  7  /
ORA-06512: at "SCOTT.P1", line 4
ORA-06512: at "SCOTT.P2", line 5
ORA-06512: at
line 2


PL/SQL procedure successfully completed.

Answer 2

或者试试 DBMS_UTILITY.FORMAT_CALL_STACK

Answer 3

我使用了DBMS_UTILITY.FORMAT_ERROR_STACK和DBMS_UTILITY.FORMAT_ERROR_BACKTRACE的组合。（改善贾斯汀·凯夫的答案）

when others then
  Dbms_Output.put_line ( DBMS_UTILITY.FORMAT_ERROR_STACK() );
  Dbms_Output.put_line ( DBMS_UTILITY.FORMAT_ERROR_BACKTRACE() );

这在第一行给出了错误，而在随后的几行给出了堆栈：（从贾斯汀·凯夫给出的例子中输出）

ORA-20001: Error 1
ORA-06512: at "SCOTT.X1", line 4
ORA-06512: at "SCOTT.X2", line 5
ORA-06512: at line 2

Answer 4

或者你可以使用 DBMS_DEBUG.PRINT_BACKTRACE