Muh*_*uhd 234 sql oracle sql-update
表格1:
id    name    desc
-----------------------
1     a       abc
2     b       def
3     c       adf
表2:
id    name    desc
-----------------------
1     x       123
2     y       345
在oracle SQL中,如何运行可以使用表2更新表1 并使用相同的sql更新查询?所以我得到的最终结果是namedescid
表格1:
id    name    desc
-----------------------
1     x       123
2     y       345
3     c       adf
问题来自更新一个表与来自另一个表的数据,但专门针对oracle SQL.
Jus*_*ave 482
这称为相关更新
UPDATE table1 t1
   SET (name, desc) = (SELECT t2.name, t2.desc
                         FROM table2 t2
                        WHERE t1.id = t2.id)
 WHERE EXISTS (
    SELECT 1
      FROM table2 t2
     WHERE t1.id = t2.id )
假设连接导致密钥保留视图,您也可以
UPDATE (SELECT t1.id, 
               t1.name name1,
               t1.desc desc1,
               t2.name name2,
               t2.desc desc2
          FROM table1 t1,
               table2 t2
         WHERE t1.id = t2.id)
   SET name1 = name2,
       desc1 = desc2
Adr*_*ian 104
试试这个:
MERGE INTO table1 t1
USING
(
-- For more complicated queries you can use WITH clause here
SELECT * FROM table2
)t2
ON(t1.id = t2.id)
WHEN MATCHED THEN UPDATE SET
t1.name = t2.name,
t1.desc = t2.desc;
Yah*_*hia 18
尝试
UPDATE Table1 T1 SET
T1.name = (SELECT T2.name FROM Table2 T2 WHERE T2.id = T1.id),
T1.desc = (SELECT T2.desc FROM Table2 T2 WHERE T2.id = T1.id)
WHERE T1.id IN (SELECT T2.id FROM Table2 T2 WHERE T2.id = T1.id);
小智 9
Update table set column = (select...)
从来没有为我工作,因为set只需要1个值 - SQL错误:ORA-01427:单行子查询返回多行.
这是解决方案:
BEGIN
For i in (select id, name, desc from table1) 
LOOP
Update table2 set name = i.name, desc = i.desc where id = i.id;
END LOOP;
END;
这就是你如何在SQLDeveloper工作表上运行它.他们说这很慢,但这是唯一能在这种情况下对我有用的解决方案.
这里似乎是一个更好的答案,'in'子句允许连接的多个键:
update fp_active set STATE='E', 
   LAST_DATE_MAJ = sysdate where (client,code) in (select (client,code) from fp_detail
  where valid = 1) ...
完整的示例如下:http: //forums.devshed.com/oracle-development-96/how-to-update-from-two-tables-195893.html
牛肉是在"in"之前的where子句中使用您想要用作括号中的键的列,并且在括号中使用具有相同列名的select语句.where(column1,column2)in(select(column1,column2)from table from table"I want");