激活参数在 GridSearch 中不起作用

Question

我正在尝试为最佳参数创建 GridSearch，如下所示：

def MultiPerceptron(optimizer = 'adam', loss = 'binary_cross_entropy', kernel_initializer = 'random_uniform', activation = 'relu', units = 16):
  model = Sequential()
  model.add(InputLayer(30))
  model.add(Dense(units = units, activation = activation, kernel_initializer = kernel_initializer))
  model.add(Dense(units = units, activation = activation, kernel_initializer = kernel_initializer))
  model.add(Dense(units = 1, activation = 'sigmoid'))
  model.compile(optimizer = optimizer, loss = loss, metrics =['binary_accuracy'])
  return model

classifier = KerasClassifier(build_fn = MultiPerceptron, validation_split = 0.1, validation_batch_size = 50)
param = {'batch_size': [10, 30],
         'epochs': [50, 100],
         'optimizer': ['adam', 'sgd'],
         'loss': ['binary_crossentropy', 'hinge'],
         'kernel_initializer': ['random_uniform', 'normal'],
         'activation': ['relu', 'tanh'],
         'units': [16, 8]}

search = GridSearchCV(estimator = classifier, param_grid = param, scoring = 'accuracy', cv = 5)
search = search.fit(x,y)

我收到以下错误：

ValueError: Invalid parameter activation for estimator KerasClassifier.
This issue can likely be resolved by setting this parameter in the KerasClassifier constructor:
`KerasClassifier(activation=relu)`
Check the list of available parameters with `estimator.get_params().keys()`

Answer 1

我认为他们改变了一些东西，因为我只能让它工作activation=relu将参数传递给KerasClassifier.

那里不需要其他参数。