我正在尝试使用XPath来解析XML字符串,但我只返回空值.有没有人知道下面的代码我可能会出错?
public static void main(String[] args) {
String content = "<imagesXML><Images><Image><ImageUID Scope='Public' Type='Guid' Value='{7f2535d0-9a41-4997-9694-0a4de569e6d9}'/><CorbisID Scope='Public' Type='String' Value='42-15534232'/><Title Scope='Public' Type='String' Value='Animal'/><CreditLine Scope='Public' Type='String' Value='© Robert Llewellyn/Corbis'/><IsRoyaltyFree Scope='Public' Type='Boolean' Value='False'/><AspectRatio Scope='Public' Type='String' Value='1.500000'/><URL128 Scope='Public' Type='String' Value='http://cachens.corbis.com/CorbisImage/thumb/15/53/42/15534232/42-15534232.jpg'/></Image></Images></imagesXML>";
InputSource source = new InputSource(new StringReader(content));
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList list = null;
try {
list = (NodeList) xPath.evaluate("//URL128[@Value]", source,
XPathConstants.NODESET);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
for (int i = 0; i < list.getLength(); i++) {
System.out.println(list.item(i));
}
}
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从System.out的输出是"值= [URL128:空]",但它应该是我试图提取的网址:http://cachens.corbis.com/CorbisImage/thumb/15/53/42/15534232/42-15534232.jpg.
任何帮助表示感谢,谢谢.
如果您尝试更改此XPath评估语句,该怎么办:
list = (NodeList)xPath.evaluate("//URL128[@Value]",
source, XPathConstants.NODESET);
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对此:
list = (NodeList) xPath.evaluate("//URL128/@Value",
source, XPathConstants.NODESET);
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