Java:编组对象 - 在xml中删除额外的ns2注释

Question

我试图根据定义的模式将对象中的数据编组到xml文件中.但是,当我打印出xml文件时,我在xml标签上收到了额外的注释.有没有办法摆脱额外的命名空间注释(即ns2)

这是我从编组中收到的xml的一个例子.

<?xml version="1.0" encoding="UTF-8" standalone="yes">
<root xmlns:ns2="http://www.something.com/something">
    <ns2:food>steak</ns2:food>
    <ns2:beverage>water</ns2:beverage>
</root>

我想要的是这样的:

<?xml version="1.0" encoding="UTF-8" standalone="yes">
<root xmlns="http://www.something.com/something">
    <food>steak</food>
    <beverage>water</beverage>
</root>

这就是我的Java代码正在做的事情:

            JAXBContext context = JAXBContext.newInstance("com.schema");
            JAXBElement<FoodSchema> element = new JAXBElement<FoodSchema>
                (new QName("FoodSchema"), Food.class, foodSchema);
            Marshaller marshaller = context.createMarshaller();
            OutputStream os = new FileOutputStream(object.getFilePath());
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); 
            marshaller.marshal(element, os);

任何帮助深表感谢!谢谢!

Answer 1

通过向QName用于构造JAXB元素的命名空间URI("http://www.something.com/something")添加命名空间URI ,并利用包级别@XmlSchema注释将获得您正在寻找的命名空间限定条件:

包信息

@XmlSchema(
    namespace="http://www.something.com/something", 
    elementFormDefault=XmlNsForm.QUALIFIED)
package forum7014746;

import javax.xml.bind.annotation.*;

餐饮

package forum7014746;

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Food {

    private String food;
    private String beverage;

    public String getFood() {
        return food;
    }

    public void setFood(String food) {
        this.food = food;
    }

    public String getBeverage() {
        return beverage;
    }

    public void setBeverage(String beverage) {
        this.beverage = beverage;
    }

}

演示

package forum7014746;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.Marshaller;
import javax.xml.namespace.QName;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jaxbContext = JAXBContext.newInstance(Food.class);

        Food foodSchema = new Food();
        foodSchema.setFood("steak");
        foodSchema.setBeverage("water");

        JAXBElement<Food> element = new JAXBElement<Food> (new QName("http://www.something.com/something","FoodSchema"), Food.class, foodSchema);

        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(element, System.out);
    }

}

产量

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<FoodSchema xmlns="http://www.something.com/something">
    <beverage>water</beverage>
    <food>steak</food>
</FoodSchema>

Answer 2

添加到 xsd 架构定义elementFormDefault和attributeFormDefault：

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" ...
elementFormDefault="qualified" attributeFormDefault="unqualified" ... >