创建未知类型的数组

Question

我有一个对象,我必须验证问题的值,对象的一些属性是自定义对象的数组.这将涉及到一些无聊的阵列的各个元素.为每个元素执行getter,例如:

AttribGrp[] x =  Object.getAttribGrp()
x[i].getSomeValue()

我需要这样做.我已经使用带有属性列表的Enum提取数据.按以下方式.

public String getAttribValueAsString(MethodEnum attribName) 
{
    String attribValue = null;
    Object value = getAttrib(attribName.toString());

    if (value != null)
        attribValue = value.toString();

    return attribValue;
}

电话:

    private Object invoke(String methodName, Object newValue)
{
    Object value = null;
    try
    {
        methodInvoker.setTargetMethod(methodName);

        if (newValue != null)
            methodInvoker.setArguments(new Object[]{newValue});
        else
            methodInvoker.setArguments(new Object[]{});             

        methodInvoker.prepare();
        value = methodInvoker.invoke();
    }
    catch (ClassNotFoundException e)
    {
        throw new IllegalStateException("Method invocation failed. " + e.getMessage(),e);
    }
    catch (NoSuchMethodException e)
    {
        throw new IllegalStateException("Method invocation failed. " + e.getMessage(),e);
    }
    catch (InvocationTargetException e)
    {
        throw new IllegalStateException("Method invocation failed. " + e.getMessage(),e);
    }
    catch (IllegalAccessException e)
    {
        throw new IllegalStateException("Method invocation failed. " + e.getMessage(),e);
    }
    return value;
}

我将在阵列中使用许多不同类型和不同值的数组.我想创建一个方法如下.

    public Object getAttribArray(RIORepeatingGrpEnum repeatingGrp)
{
        repeatingGrp[] grp = null;
              Object grpVal = getAttrib(repeatingGrp.toString());
              if(grp != null)
                   grp = (repeatingGrp[]) grpVal;

              return grp;
}

这给了我多个主要与repeatGrp []有关的错误.数组类型应与枚举名称相同.是否有可能创建一个这样的方法来创建一个未定义类型的数组？

Answer 1

如果您想拥有未知类型的数组，请使用泛型：

 public <T> T[] getAttribArray(Class<T> repeatingGrpClass)
 {
    //get the attribute based on the class (which you might get based on the enum for example)
    return (T[]) getAttrib( repeatingGrpClass.getName() ); //note that you might want to use the class object instead of its name here
 }